The given question is incomplete. The complete question is :
What volume of 0.160 M solution of KOH must be added to 550.0 mL of the acidic solution to completely neutralize all of the 0.150 M hydrochloric acid?
Answer: Volume in liters to three significant figures is 0.516 L
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH
We are given:
Putting values in above equation, we get:
(1L=1000ml)
Thus volume in liters to three significant figures is 0.516 L
Listed below are the inter-molecular bonding that exists in the compound <span>ch3ch2ch2ch2ch2ch2oh.
1. Hydrogen Bonding- The type of bonding that exist between O-H in the compound.
2. Dipole-Dipole Bonding- The type of Bonding that is created when the electronegative draws more electron to its self. Exists between C-O
3. London Dispersion- Created between C-H bonding.</span>
I’m sorry but I did not understand the question
Answer:
Relative humidity is low .
Explanation:
The wet bulb reads low temperature because due to low humidity of atmosphere , evaporation of water takes place from the wet bulb which makes the bulb cool and therefore it reads lower temperature . In the process of evaporation , heat equal to latent heat of vaporization is taken from the bulb and it loses temperature.
