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Igoryamba
3 years ago
10

According to the molecular orbital (mo) treatment of the no molecule, what are the bond order and the number of unpaired electro

ns, respectively?

Chemistry
1 answer:
mojhsa [17]3 years ago
3 0
Attached is the MOT of NO molecule.

1. Bond order is calculated is \frac{\text{number of e- in bonding orbital - number of e- in antibonding molecular orbital }}{2}

In present case, number of e- in bonding orbital = 6
number of e- in anti-bonding orbital = 1
∴ Bond-order = \frac{\text{6-1 }}{2} = 2.5

2. From the attached figure, it can be seen that NO has one unpaired electron in π* orbital.
 

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The valence electrons found in metallic bonds are different from other bonds<br> because
4vir4ik [10]

Answer:

The valence electrons in the metal atom in the lattice structure can delocalize and move freely. The electrons are "loosely" connected with their parent atom in the metallic bond because most metals have excess electrons in their outer orbitals above the stable configuration.

Explanation:

Says google

5 0
3 years ago
What is the name of this molecule?<br><br> H3C - C ≡ C - CH3<br><br> Answer: 1,2,3, or 4-butyne?
Semenov [28]

Explanation:

The given molecule is

H3C - C ≡ C - CH3

The numbering order is shown below:

H3C - C ≡ C - CH3

    1     2     3     4

So, the alkyne group is in the second position.

The carbon chain has four carbons.

Hence, the IUPAC name of the given compound is:

2-butyne.

8 0
3 years ago
What gasous product would you expect when water is drop over calcium carbide​
wolverine [178]

Answer:

Ethyn gas ( acetylene gas )

Explanation:

All group II carbides react with water to form ethyn gas apart from beryllium which produces methane gas.

{ \sf{CaC_{2(s)}  +  2H _{2} O_{(l)}  → Ca(OH) _{2(s)}  + C _{2} H _{2(g)} }}

7 0
3 years ago
The conversion of the fatty acid palmitate (c16) to carbon dioxide via β-oxidation, the citric acid cycle and oxidative phosphor
Semmy [17]

The conversion of the fatty acid palmitate (C-16) to carbon dioxide via β-oxidation, the citric acid cycle and oxidative phosphorylation yield approximately <u>106 atp</u> equivalents.

The most prevalent kind of fatty acid with sixteen carbon atoms without carbon-carbon double bonds would be palmitic acid. There must be a maximum of seven cycles of beta-oxidation in order to totally degrade the fatty acid. 8 acetyl-CoA molecules, 7 NADH molecules, with 7 FADH2 molecules are produced as a result of this.

The primary enzyme, CAT-1, catalyzes the production of acylcarnitine carnitine, which provides the rate-limiting step in beta-oxidation.

Therefore, the conversion of the fatty acid palmitate (C-16) to carbon dioxide via β-oxidation, the citric acid cycle and oxidative phosphorylation yield approximately <u>106 atp</u> equivalents.

To know more about fatty acid

brainly.com/question/13528495

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6 0
2 years ago
1 mole = 6.02 x 10^23 molecules. 1 mole= 22.4 L How many liters does 5.0 x 10^24 molecules occupy? .37 L 1.3 x10^49 L 190L or 6.
alexandr1967 [171]

Answer:

185.92  L

Explanation:

Given data:

1 mole = 6.022× 10²³ molecules

1 mole = 22.4 L

Volume occupy by 5.0× 10²⁴ molecules

Solution:

1 mole = 6.022× 10²³ molecules

5.0× 10²⁴ molecules × 1 mole / 6.022× 10²³ molecules

0.83× 10¹ mol

8.3 moles

1 mole occupy 22.4 L

8.3 mol × 22.4 L / 1 mol

185.92  L

4 0
3 years ago
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