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Igoryamba
3 years ago
10

According to the molecular orbital (mo) treatment of the no molecule, what are the bond order and the number of unpaired electro

ns, respectively?

Chemistry
1 answer:
mojhsa [17]3 years ago
3 0
Attached is the MOT of NO molecule.

1. Bond order is calculated is \frac{\text{number of e- in bonding orbital - number of e- in antibonding molecular orbital }}{2}

In present case, number of e- in bonding orbital = 6
number of e- in anti-bonding orbital = 1
∴ Bond-order = \frac{\text{6-1 }}{2} = 2.5

2. From the attached figure, it can be seen that NO has one unpaired electron in π* orbital.
 

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