According to the molecular orbital (mo) treatment of the no molecule, what are the bond order and the number of unpaired electro

Question

Igoryamba

3 years ago

10

According to the molecular orbital (mo) treatment of the no molecule, what are the bond order and the number of unpaired electro

ns, respectively?

Chemistry

1 answer:

mojhsa [17] · Answer 1 · 2022-06-01T11:48:41+03:00

Attached is the MOT of NO molecule.

1. Bond order is calculated is $\frac{\text{number of e- in bonding orbital - number of e- in antibonding molecular orbital }}{2}$

In present case, number of e- in bonding orbital = 6
number of e- in anti-bonding orbital = 1
∴ Bond-order = $\frac{\text{6-1 }}{2}$ = 2.5

2. From the attached figure, it can be seen that NO has one unpaired electron in π* orbital.