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2 years ago

Sayyy I need help on dis work

Mathematics

1 answer:

LenKa [72]2 years ago

4 0

There is nothing there sorry

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The total number of cupcakes Carmen can bake depends on the amount of time she spends baking. Carmen can bake 84 cupcakes in 1.6

Vitek1552 [10]

We know that the number of cakes is dependent on the time spent in baking.

We are given that Carmen can bake 84 cakes in 1.6 hours, therefore, to know the number of cakes that she can bake in 2 hours, all you have to do is cross multiplication as follows:
number of cakes = (2*84) / 1.6 = 105 cakes

8 0

3 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Tom [10]

Stokes' theorem says the integral of the curl of $\vec F$ over a surface $S$ with boundary $C$ is equal to the integral of $\vec F$ along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

$\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r$

We have

$\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=4\,\vec k$

Parameterize the ellipse $S$ by

$\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath$

with $0\le u\le1$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k$

Then the flux of the curl is

$\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}$

4 0

3 years ago

Describe in words the region of R3 reperesented by the equations or inequalities x2+y2=4,z=-1

Roman55 [17]

Answer:

It represents a circle of radius 2, centered in the origin of the plane xy and transversal to the z-axis in z=-1.

Step-by-step explanation:

The first thing to notice is that

$x^2+y^2=2^2$

<u>represents a circle of radius 2</u>, with its center in the origin of a plane xy, of cartesians coordinates.

Starting from here, we have to put the coordinate z, to complete the space R³. <em>Then, the cirlce will "live" into the plane xy, where z=-1</em>.

Finally, we have that this region is a circle of radius 2, centered in the origin of the plane xy, and transversal to z=-1.

8 0

3 years ago

Which package has the lowest ratio of cost to number of lesson

Ilya [14]

Can you be a little more specific? Put the whole question or something... Hope I can help! :)

4 0

3 years ago

(08.07A LC)

shtirl [24]

Answer:

Step-by-step explanation:

you would do the total which is 45-20

5 0

3 years ago