Answer:
Decomposers (either Secondary Consumer or Tertiary Consumer)
Explanation:
Decomposers eat dead materials and break them down into chemical parts. ... They keep the ecosystem free of the bodies of dead animals or carrion. They break down the organic material and recycle it into the ecosystem as nutrients. Vultures, Blowflies, hyenas, crabs, lobsters and eels are examples of scavengers.
Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles
The answer to this question would be: 3.125%
Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
The atomic mass of K is 39
from Avogadro's law
39g of K contains 6.02x10^23 atoms
therefore if
39=6.02x19^23
X=5.11×10^22
making X the subject of the formula
X= (5.11×10^22×39)÷6.02×10^23
X= 33g
Answer:
Explanation:
Given that,
The distance between the centers of the two oxygen atoms in an oxygen molecule is 
.
We need to convert this distance in inches.
We know that,
1 cm = 0.393 inches
We can solve it as follows :
So, the distance between the centers of the two oxygen atoms is 
.
