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horsena [70]
3 years ago
5

4) 4 NH3 + 3 O2  2 N2 + 6 H2O

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
6 0
4 NH₃ + 3O₂ --> 2N₂ + 6H₂O

First, make sure that this is a balanced equation.
There are 4 moles of nitrogen on the left side, and 4 moles of nitrogen on the right side.
There are 12 moles of hydrogen on the left side, and 12 moles of hydrogen on the right side.
There are 6 moles of oxygen on the left side, and 6 moles of oxygen on the right side.

The equation is therefore balanced, and we may proceed.

a) the mole ratio for NH₃ to N₂ is 4 to 2, which can be simplified to 2:1 or 2/1.

b) the mole ratio for H₂O to O₂ is 6 to 3, which can be simplified to 2:1 or 2/1.
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As the water molecules re-freeze, what happens to the salt ions that are mixed in with the water?
Murljashka [212]

Answer:

Explanation:

Since salt is composed of two ions Na+ and Cl- it will attract to the opposite poles of the water and form a ion-dipole bond. This will cause the phenomenon freezing point depression where as the name states it will take a lower tempertature to freeze it. So instead of freezing at 0 degrees c it will freeze at a negative 2 or so on.

5 0
3 years ago
HELP PLSSSSS!!
11Alexandr11 [23.1K]

Answer:

68133080.02 g

Explanation:

I believe that the question is to find the mass of air in the room and not the molar mass of air since the molar mass of air was already given in the question as 28.97 g/mol.

Now, if 1 mole of a gas occupies 22.4 L

x moles of air occupies 52,681,428.8 Liters

x = 1 * 52,681,428.8 /22.4

x = 2351849.5 moles of air

Now, number of moles = mass/ molar mass

but molar mass = 28.97 g/mol

2351849.5 = mass/28.97

mass = 2351849.5 * 28.97

mass = 68133080.02 g

7 0
3 years ago
A 1.5L intraveneous (IV) solution contains 919 grams glucose (C6H12O6). What is the molarity of this solution?
AleksandrR [38]

Answer:

3.4 M

Explanation:

M = grams/molar mass = ans./volume(L)

M = 919/180 = ans./1.5

3 0
3 years ago
What is the empirical formula for a compound that contains 79.86 % iodine and 20.14 % oxygen by mass?
serg [7]

Answer:

IO₂

Explanation:

We have been given the mass percentages of the elements that makes up the compound:

Mass percentage given are:

Iodine = 79.86%

Oxygen = 20.14%

To calculate the empirical formula which is the simplest formula of the compound, we follow these steps:

> Express the mass percentages as the mass of the elements of the compound.

> Find the number of moles by dividing through by the atomic masses

> Divide by the smallest and either approximate to nearest whole number or multiply through by a factor.

> The ratio is the empirical formula of the compound.

Solution:

I O

% of elements 79.86 20.14

Mass (in g) 79.86 20.14

Moles(divide by

Atomic mass) 79.86/127 20.14/16

Moles 0.634 1.259

Dividing by

Smallest 0.634/0.634 1.259/0.634

1 2

The empirical formula is IO₂

7 0
3 years ago
When copper ii chloride reacts with sodium nitrate copper ii nitrate and sodium chloride are formed?
Nesterboy [21]
The balanced chemical reaction would be written as follows:

CuCl2 + 2NaNO3 = Cu(NO3)2 + 2NaCl

This is an example of a double displacement type of reaction where the ions of the reactants displaces each other forming two new substances. Hope this answers the question.
5 0
3 years ago
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