All categories

2 years ago

What are the coefficients that balance the following chemical equation? _Ag + _ S → ___Ag2S

Chemistry

2 answers:

Tanya [424]2 years ago

4 0

Answer:

$2Ag+S$ → $Ag_2S$

Explanation:

In order to balance this, we want to have the same number of elements on each side of the equation.

On the right side, we see that we have two atoms of Ag and one atom of S. So on the left, we want to have 2 atoms of Ag and 1 atom of S. We can put 1 in front of S and 2 in front of Ag:

2Ag + 1S → 1 $Ag_2S$

We actually don't have to explicitly write the "1":

$2Ag+S$ → $Ag_2S$

Hope this helps!

Andrej [43]2 years ago

3 0

Answer:

1Ag+2S⇔1Ag2S

Explanation:

The first step is to see how many of each element are on each side of the equation. There is one silver on the left and one silver on the right, so you can leave those alone. However, there is one sulfur on the left and two on the right. You cannot multiply the right by 2 because then that would upset the balance of the silver, but you can multiply the sulfur by 2. Therefore, the equation should be 1Ag+2S⇔1Ag2S. Hope this helps!

You might be interested in

A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and

Romashka [77]

Answer: The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

Explanation:

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(S_8)$ = 0.800 g

$M_{solute}$ = Molar mass of solute $(S-8)$ = 256.52 g/mol

$W_{solvent}$ = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m$

Calculation for freezing point of solution:

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

$\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

or,

$\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm$

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC$

Hence, the freezing point of solution is 16.5°C

Calculation for boiling point of solution:

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

or,

$\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm$

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC$

Hence, the boiling point of solution is 118.2°C

8 0

3 years ago

A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and

IrinaK [193]

Answer:

34.02 g.

Explanation:

Hello!

In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:

$PV=nRT\\\\n=\frac{1.00atm*0.960L}{0.08206\frac{atm*L}{mol*K}*(150+273)K} =0.0277mol\\\\$

Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:

$MM=\frac{0.941g}{0.0277mol} \\\\MM=34.02g/mol$

So probably, the gas may be H₂S.

Best regards!

6 0

3 years ago

What is the [H+] if the pH is 13.6?

MrRa [10]

Answer:

8???

Explanation:

i honestly don't know???

8 0

3 years ago

Read 2 more answers

Which of the following is a property of carbon atoms?

marusya05 [52]

Answer:

B. They can for covalent bonds with other atoms.

Explanation:

Carbon = King of the elements on the periodic table

For its proclivity to form stable covalent bonds with multivalent atoms.

5 0

3 years ago

Read 2 more answers

sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a

Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

$P_1T_2=P_2T_1$

Where, $T_1$ and $T_2$ are initial and final temperatures, $P_1$ and $P_2$ are initial and final pressures.

$T_1$ = 20.3 + 273.15 = 293.45 K

$T_2$ = -2.0 + 273.15 = 271.15 K

$P_1$ = 1.02 atm

$T_2$ = ?

Let's plug in the values in the equation and solve it for final pressure.

$1.02atm(271.15K)=P_2(293.45K)$

$P_2=\frac{1.02atm*271.15K}{293.45K}$

$P_2$ = 0.942 atm

So, the new pressure of the jar is 0.942 atm.

5 0

3 years ago

What are the coefficients that balance the following chemical equation? ___Ag + ___ S → ___Ag2S

What are the coefficients that balance the following chemical equation? _Ag + _ S → ___Ag2S