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jolli1 [7]
3 years ago
12

What are the coefficients that balance the following chemical equation? ___Ag + ___ S → ___Ag2S

Chemistry
2 answers:
Tanya [424]3 years ago
4 0

Answer:

2Ag+S → Ag_2S

Explanation:

In order to balance this, we want to have the same number of elements on each side of the equation.

On the right side, we see that we have two atoms of Ag and one atom of S. So on the left, we want to have 2 atoms of Ag and 1 atom of S. We can put 1 in front of S and 2 in front of Ag:

2Ag + 1S → 1Ag_2S

We actually don't have to explicitly write the "1":

2Ag+S → Ag_2S

Hope this helps!

Andrej [43]3 years ago
3 0

Answer:

1Ag+2S⇔1Ag2S

Explanation:

The first step is to see how many of each element are on each side of the equation. There is one silver on the left and one silver on the right, so you can leave those alone. However, there is one sulfur on the left and two on the right. You cannot multiply the right by 2 because then that would upset the balance of the silver, but you can multiply the sulfur by 2. Therefore, the equation should be 1Ag+2S⇔1Ag2S. Hope this helps!

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ivolga24 [154]

<u>Answer:</u> The equilibrium concentration of bromine gas is 0.00135 M

<u>Explanation:</u>

We are given:

Initial concentration of chlorine gas = 0.0300 M

Initial concentration of bromine monochlorine = 0.0200 M

For the given chemical equation:

                   2BrCl\rightleftharpoons Br_2+Cl_2

<u>Initial:</u>          0.02               0.03

<u>At eqllm:</u>    0.02-2x     x     0.03+x

The expression of K_c for above equation follows:

K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}

We are given:

K_c=0.141

Putting values in above equation, we get:

0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135

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3 years ago
Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu
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Answer:

5000 and 8\times 10^{7} indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: K=\frac{[B]}{[A]}

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

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he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
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2) 5.6\cdot 10^{13} electrons per person

Explanation:

1)

For a current flowing through a conductor, the drift velocity of the electrons is given by the equation:

v_d=\frac{I}{neA}

where

I is the current

n is the concentration of free electrons

e=1.6\cdot 10^{-19}C is the electron charge

A is the cross-sectional area of the wire

The cross-sectional area can be written as

A=\pi r^2

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v_d=\frac{I}{ne\pi r^2}

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I = 8.0 A is the current

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d = 1.5 mm is the diameter, so the radius is

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

Therefore, the drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

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The total length of the cord in this problem is

L = 3.00 m

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N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

In total, the Earth population consists of 8 billion people, which is

N'=8\cdot 10^9

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N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

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