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Nezavi [6.7K]
3 years ago
10

What chemical processes do producers and consumers share and do not share

Chemistry
1 answer:
Oksanka [162]3 years ago
7 0
They share <span>cellular respiration, but they don't share the same process (producers use Photosynthesis). Did this help? :D</span>
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How many moles of copper are needed to react with sulfur to produce 0.25 moles Ol
Tems11 [23]

Answer:

                       0.50 moles of Cu

Explanation:

                    The balanced chemical equation for given synthetic reaction is,

                                          2 Cu + S → Cu₂S

According to balance chemical equation,

                  1 mole of Cu₂S is produced by  =  2 moles of Cu

So,

          0.25 moles of Cu₂S will be produced by  =  X moles of Cu

Solving for X,

                      X  =  0.25 mol × 2 mol /  1 mol

                      X  =  0.50 moles of Cu

Hence, as the molar ratio of Cu to Cu₂S is 2:1 hence, to produce 0.25 moles of Cu₂S we will need 0.50 moles of Cu.

6 0
3 years ago
How can you chose values for x when making a table of values representing a real world situation?
Nitella [24]
X is usually representing time so years, days, etc
7 0
3 years ago
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
Which one of the atoms shown would be most likely to form a cation with a charge of 1?
olga55 [171]
Ions are stable atoms of elements formed when original atoms loose or gain electrons to form stable configuration. Anions are negatively charged ions formed when atoms gain electrons while cations are the positively charged ions formed when atoms loose electrons. In this case a charge of +1 means an atom lost one electron to form a stable configuration. Therefore, the correct answer is A
6 0
3 years ago
Read 2 more answers
an aqueous solution contains 1.2mM of total ions. if the solution is NaCl (aq), what is the concentration of chloride ions?
Genrish500 [490]

Explanation:

As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.

As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.

           NaCl \rightarrow Na^{+} + Cl^{-}

So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.

Therefore, concentration of chlorine ions will be calculated as follows.

       Concentration of Cl^{-} ions = \frac{1.2mM}{2}

                                                        = 0.6 mM

Thus, we can conclude that the concentration of chloride ions is 0.6 mM.

5 0
3 years ago
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