All categories

4 years ago

If f(x) = 2x^2 - x, find f(-3).

Mathematics

2 answers:

Tju [1.3M]4 years ago

7 0

F(x)=2x^2-x, x=-3

f(-3)=2(-3)^2-(-3)

f(-3)=2(9)+3

f(-3)=18+3

f(-3)=21

ioda4 years ago

4 0

F(-3) = 2(-3)^2 - (-3) = 2(9)+3 = 18 + 3 = 21

You might be interested in

If the pile contains only 15 quarters but at least 30 of each other kind of coin, how many collections of 30 coins can be chosen

klio [65]

<span>My answer to your question would be: C(33,3)-C(17,3). </span>I hope that this is the answer that you were looking for and it has helped you.

6 0

4 years ago

Which percent is equivalent to ?

AleksAgata [21]

It would be 340%. First, you need to find out what the fraction is for 2/5. 2/5 as a decimal would be .4. Next you put that back with the three which is 3.4. After that, you need to turn that into a percentage by multiplying it by 100 which then equals 340. add the % to it and that gives you 340%.

3 0

3 years ago

Read 2 more answers

(6x2 -5x + 10) - (2x2 -x +13)

Sidana [21]

Answer:

-4x + 5 ?

sorry if wrong

6 0

3 years ago

Chris has $3.30 in nickels and quarters. If she has twice as many quarters as nickels, how many of each coin does she have?

AleksAgata [21]

Answer:

she has 12 quarters and 6 nickels 6×.05 =.30 12×.25=3.00

8 0

4 years ago

a picture 10 1/4 feet long is to be centered on a wall that is 14 1/2 feet long. How much more space is there from the edge of t

Zarrin [17]

Answer:

Length from the edge will be $=2{\frac{1}{8}}$ feet

Step-by-step explanation:

To find length we have to conver mixed fraction to improper fraction

The length of the wall $= \frac{29}{2}$

Length of picture $=\frac{41}{4}$

First we find the total length of wall remain after picture was hung to the wall.

Length of wall remain vacant $=\frac{29}{2}-\frac{41}{4}$

Taking LCM and solving we get

$=\frac{58-41}{4} =\frac{17}{4}$

Total length of wall remain vacant $=\frac{17}{4}$

As the picture to be centered in wall, therefore space feom one edge of wall will be half that of length remain vacant as the same length to be left vacant feom both sides.

Space from one edge $=\frac{17}{4} \times \frac{1}{2}$

$= \frac{17}{8}$

$=2{\frac{1}{8}}$

Length from the edge will be $=2{\frac{1}{8}}$ feet

6 0

4 years ago