Solve the equation.

2 answers:

4 0

Ok, so if you have xy=0, then assume that x and y are equal to 0
so we have
(4n+5)(3n-7)=0
assue that
4n+5=0 and 3n-7=0

solve those
4n+5=0
minus 5
4n=-5
divide by 4
n=-5/4

3n-7=0
add 7
3n=7
divide 3
n=7/3

-5/4 and 7/3

2nd option

zvonat [6]4 years ago

3 0

You can set each equation to 0 so it would look like this:
And solve

4n+5=0. 3n-7=0
-5=-5. +7=+7

4n = 5. 3n = 7
4n/4 = 5/4. 3n/3 = 7/3
n = 5/4 n = 7/3

The first set of answers are the correct answers for n.

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Train completes journey of 150 miles one hour earlier if original speed is increased by 5mes/hour What is original speed

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this is because you are adding 5mph, and taking off 1 hour of time, to still cover the 150 miles. you can solve the first equation for t, and substitute into the second, and then solve for x.
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Option 3

The solution for given expression is $\frac{(x - 4)(x - 4)}{(x + 3)(x + 1)}$

<h3><u>Solution:</u></h3>

Given that we have to divide,

$\frac{x^2 -16}{x^2 + 5x + 6} \div \frac{x^2 + 5x + 4}{x^2 -2x - 8}$ ---- (A)

Let us first factorize each term and then solve the sum

Using $a^2 - b^2 = (a + b)(a - b)$

$x^2 -16 = x^2 - 4^2 = (x + 4)(x -4)$ ----- (1)

$x^2 + 5x + 6 = (x + 2)(x + 3)$ ----- (2)

$x^2 + 5x + 4 = (x+1)(x + 4)$ ---- (3)

$x^2 -2x - 8 = (x-4)(x + 2)$ ---- (4)

Now substituting (1), (2), (3), (4) in (A) we get,

$\frac{(x + 4)(x -4)}{(x +2)(x +3)} \div \frac{(x+1)(x+4)}{(x-4)(x +2)}$

To do division with fractions, we turn the second fraction upside down and change the division symbol to a multiplication symbol at the same time. Then we treat this as a multiplication problem, by multiplying the numerators and the denominators separately.

$\frac{(x + 4)(x -4)}{(x +2)(x +3)} \times \frac{(x - 4)(x + 2)}{(x + 1)(x + 4)}$