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svetoff [14.1K]
3 years ago
7

What is the magnitude of the net force ona(n) 97 kg driver operating a dragster as it accelerates horizontally along a straight

line from rest to 40 m/s in 5 s?
Physics
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

Force acting on the driver will be 776 N

Explanation:

We have given mass of the driver m = 97 kg

It starts from rest so initial velocity u = 0 m /sec

And reaches to a velocity of 40 m /sec in 5 sec

So final velocity v = 40 m /sec

And time taken t = 5 sec

From first equation of motion v = u +at

So 40=0+a\times 5

a=8m/sec^2

Now we have to find the force acting the driver

From newtons law we know that F = ma

So force F = 97×8 = 776 N

So force acting on the driver will be 776 N

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Answer:

% reduction in area = 54.26 %

percentage elongation = 43.16 %

Explanation:

a) percentage reduction in area = \frac{(A_1 - A_2)}{A_1 } * 100

A_1  =\pi r^2 = \pi * 5.88^2=108.8 mm2

A_2=\pi * 3.98^2= 49.97 mm2

% reduction in area =\frac{(108.8 - 49.97)}{108.8} * 100 = 54.26 %

b)percentage elongation = \frac{(66 - 46.1)}{46.1} *100 = 43.16 %

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Because weight is a measurement of the amount of gravity pulling on an object, weight is considered a ______. Question 18 option
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Define the strip attached to the magnet?​
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In a game of tug of war, team one pulls to the right with a force of 500 newtons and team two pulls to the left with a force of
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Answer:

Explanation:

There is no set way to do this. All you have to do is define left and right. Left will be minus and right will be the opposite --- plus.

That is completely arbitrary. It could be the other way around. It does not matter.

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