Question

What is the passengers velocity on the vertical drop of the tower of terror at Disney world if the distance for the drop is 50m, and the time of the fall is 5.5s?

Answer 1

Assuming constant acceleration due to gravity of $a=9.8\,\dfrac{\mathrm m}{\mathrm s^2}$, and assuming the passengers start at rest, so that $v_0=0\,\dfrac{\mathrm m}{\mathrm s}$, we have

$v=v_0+at\implies v=\left(9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5.5\,\mathrm s)=53.9\,\dfrac{\mathrm m}{\mathrm s}$

or 54 m/s if taking significant digits into account.