The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.
<h3>What is the law of conservation of momentum?</h3>
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and m₂ will be u₁=5 and u₂=0 m/s respectively,
According to the law of conservation of momentum
Momentum before collision =Momentum after collision
m₁u₁+m₂u₂=(m₁+m₂)v
M×5+3M×0=[M+3M]v
The final velocity is found as;
V=51.25 m/s
The velocity of block A is found as;

Hence, the final velocity of the block A will be 2.5 m/sec.
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Answer: D
Key thing to keep note, is "refraction"...
Look at some experiments on YouTube, it's helps me a lot.
Answer:
figure (a) L1 is series and L2 is parallel to L3
figure (b) L2 and L3 are parallel to L1
Answer:
C. the bottom
Explanation:
The tires of the car is rolling without slipping. In this case, the bottom of the tire that contacts the surface must be at rest in order to prevent slipping. Of course this is instantaneously. The tire has a translational velocity, v, and also at the bottom a rotational velocity, -v, and the sum is zero for the bottom.