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3 years ago

Describe Newton's second Law of motion. Provide an example to support your explanation.

1 answer:

8 0

Newton's second law<span> says that acceleration of a particle is dependent on the forces acting upon the particle and the particle's mass. For a given particle, if the net force is increased, the acceleration is increased. For a given net force, the more mass a particle has, the less acceleration it has.
Ex. If you apply more force to an object, it accelerates at a higher rate, If you're pushing around a shopping cart, when you're moving at a regular pace, the cart goes at the same pace. If you accelerate your pace, the cart accelerates as well.

Hope this helps :)
-Julie</span>

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PLz I Need Help PLZZZ ASAP

AURORKA [14]

As we are increasing the frequency in the simulation the wavelength is decreasing

So if speed remains constant then wavelength and frequency depends inversely on each other

If we are in boat and and moving over very small wavelengths then these small wavelength will be encountered continuously by the boat in short interval of times

As we are changing the amplitude in the simulation there is no change in the speed frequency and wavelength.

So amplitude is independent of all these parameter

Amplitude of wave will decide the energy of wave

So light of greater intensity is the light of larger amplitude

In our daily life we deal with two waves

1 sound waves

2 light waves

3 0

3 years ago

Please help giving 15 points<br> How do you calculate the density of an object?

Elis [28]

You first find the mass and the volume of that object. Then you divide mass ÷ volume

3 0

3 years ago

Read 2 more answers

A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.

cupoosta [38]

Answer:

a) The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

Explanation:

a) The vectorial equation of momentum is represented by the following expression:

$\vec p = m\cdot \vec v$ (1)

Where:

$\vec p$ - Vector momentum, measured in kilogram-meters per second.

$m$ - Mass of the particle, measured in kilograms.

$\vec v$ - Vector velocity, measured in meters per second.

If we know that $m = 2.93\,kg$ and $\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]$ , then the momentum is:

$\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]$

$\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]$

The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of momentum are represented by the following expressions:

$\|\vec p \| = \sqrt{p_{x}^{2}+p_{y}^{2}}$ (2)

$\theta = \tan^{-1}\left(\frac{p_{y}}{p_{x}} \right)$ (3)

Where:

$\|\vec p\|$ - Magnitude of momentum, measured in kilogram-meters per second.

$\theta$ - Direction of momentum, measured in sexagesimal degrees.

If we know that $p_{x} = 8.731\,\frac{kg\cdot m}{s}$ and $p_{y} = -11.661\,\frac{kg\cdot m}{s}$ , then the magnitude and direction of momentum are, respectively:

$\|\vec p\| = \sqrt{\left(8.731\,\frac{kg\cdot m}{s} \right)^{2}+\left(-11.661\,\frac{kg\cdot m}{s} \right)^{2}}$

$\|\vec p\| \approx 14.567\,\frac{kg\cdot m}{s}$

$\theta =\tan^{-1}\left(\frac{-11.661\,\frac{kg\cdot m}{s} }{8.731\,\frac{kg\cdot m}{s} } \right)$

$\theta \approx 306.823^{\circ}$

The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

6 0

3 years ago

What change occurs to the mass of an object when an unbalanced force is applied to it

strojnjashka [21]

The mass of an object always stays the same since it is really just the amount of matter in an object so no matter the force applied, as long as the object does not lose or gain matter, the object stays the same

5 0

2 years ago

Electric power plants are the main contributors of what? Oxygen pollution, Sulfur dioxide pollution, thermal pollution, mercury

zloy xaker [14]

The correct answer is sulfur dioxide pollution

Hope this helped :)

6 0

4 years ago

Read 2 more answers