The structures and chemistry of individual hydrocarbons depend a large part on the types of chemical bonds that link together the atoms of their constituent molecules. Hydrocarbons are derived by chemical degradation.
• Bubbles of a colourless, odourless gas are evolved
• The solution turns red litmus blue
Ca + 2H_2O→ Ca(OH)_2 + H_2
Answer:
Sulfur ₁₆S³²
Explanation:
The sulfur have sixteen protons sixteen neutrons and sixteen electrons. The sum of neutrons and protons is equal to atomic mass. So the given element have sixteen protons and sixteen electron, the atomic mass would be 32 and the element with atomic mass 32 is sulfur.
The number of electrons are equal to the number of protons. In the given element two electrons are more than number of protons. It means element gain two extra electron from another element and it is present in ionic form.
It is present in given form:
S²⁻
Electronic configuration:
S₁₆ = [Ne] 3s² 3p⁴
To complete the octet sulfur gain two electrons from other element and get stable.
For
a first-order reaction, the rate law would be expressed as:<span>
r = dC / dt = -kC
Integrating it from time zero and
the initial concentration, Co, to time, t, and the final
concentration, C. We will obtain the first-order integrated law as follows:
ln C/Co= -kt
To determine the concentration of N2O in the system at a certain time, we simply substitute the given values from the problem statement
as follows:
</span>ln C / Co = -kt<span>
ln C / 10.9 = -0.76 (9.6)
e^ln C / 10.9 = e^-0.76 (9.6)
C / 10.9 = 6.78 x 10^-4
C= 7.39 x 10^-3 m
<span>
Therefore, the concentration of N2O in the system after 9.6 s would be 7.39 x10^-3 m.
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This kind of damage occurs repeatedly, it may lead to permanent damage to your lungs that could cause a lower quality of life. Ozone may aggravate chronic lung diseases, such as emphysema and bronchitis. Scientists are concerned that repeated short-term damage from ozone exposure may permanently injure the lung