Answer:
-0.1767°C (Option A)
Explanation:
Let's apply the colligative property of freezing point depression.
ΔT = Kf . m. i
i = Van't Hoff factot (number of ions dissolved). Glucose is non electrolytic so i = 1
m = molality (mol of solute / 1kg of solvent)
We have this data → 0.095 m
Kf is the freezing-point-depression constantm 1.86 °C/m, for water
ΔT = T° frezzing pure solvent - T° freezing solution
(0° - T° freezing solution) = 1.86 °C/m . 0.095 m . 1
T° freezing solution = - 1.86 °C/m . 0.095 m . 1 → -0.1767°C
Answer:
Explanation:
we are given
there are in 0.073 gallons
we can see that there are two non-zero places after decimals
so, there are two siginificant figures
step-1: Change gallons to quarts
we know that
1 gallon = 4 quarts
so, we can write as
step-2: Change into liter
we know that
1 liter = 1.057 quarts
or
step-3: Change into millilitre
we know that
Since, it is asking for only two significant figures
so, we can also write as
...................Answer
Chemical because the first thing disappeared and changed into something completely different. Because you got something new from what you started with, it is chemical.
Idk why its pumpkin spice latte but I'm not going to judge. I prefer drinking bleach.
Answer:
Explanation:
When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.
That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.
The measurement of 28.1 cm has one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.
However, the number to be dropped (51) is greater than 5 with only zeros or nothing following the 5.
You must round up the answer. You increase the last significant digit by one.
