The number of Ml of C₅H₈ that can be made from 366 ml C₅H₁₂ is 314.7 ml of C₅H₈
<u><em>calculation</em></u>
step 1: write the equation for formation of C₅H₈
C₅H₁₂ → C₅H₈ + 2 H₂
Step 2: find the mass of C₅H₁₂
mass = density × volume
= 0.620 g/ml × 366 ml =226.92 g
Step 3: find moles Of C₅H₁₂
moles = mass÷ molar mass
from periodic table the molar mass of C₅H₁₂ = (12 x5) +( 1 x12) = 72 g/mol
moles = 226.92 g÷ 72 g/mol =3.152 moles
Step 4: use the mole ratio to determine the moles of C₅H₈
C₅H₁₂:C₅H₈ is 1:1 from equation above
Therefore the moles of C₅H₈ is also = 3.152 moles
Step 5: find the mass of C₅H₈
mass = moles x molar mass
from periodic table the molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol
= 3.152 moles x 68 g/mol = 214.34 g
Step 6: find Ml of C₅H₈
=mass / density
= 214.34 g/0.681 g/ml = 314.7 ml
Answer:
No the substance is not water.
Explanation:
The balance chemical equation for the decomposition of water is as follow;
2 H₂O = 2 H₂ + O₂
Step 1: <u>Calculate moles of H₂O;</u>
Moles = Mass / M.Mass
Moles = 5.0 g / 18.01 g/mol
Moles = 0.277 moles of H₂O
Step 2: <u>Calculate Moles of O₂ and H₂ produced by 0.277 moles of H₂O:</u>
According to equation,
2 moles of H₂O produced = 1 mole of O₂
So,
0.277 moles of H₂O will produce = X moles of O₂
Solving for X,
X = 0.277 mol × 1 mol / 2 mol
X = 0.138 moles of O₂
Also,
According to equation,
2 moles of H₂O produced = 2 mole of H₂
So,
0.277 moles of H₂O will produce = X moles of H₂
Solving for X,
X = 0.277 mol × 2 mol / 2 mol
X = 0.227 moles of H₂
Step 3: <u>Calculate Mass of O₂ and H₂ as;</u>
For O₂:
Mass = Moles × M.Mass
Mass = 0.138 mol × 31.99 g/mol
Mass = 4.44 g of O₂
For H₂:
Mass = Moles × M.Mass
Mass = 0.227 mol × 2.01 g/mol
Mass = 0.559 g of H₂
Conclusion:
From conclusion it is proved that the amount of H₂ produced by decomposition of 5 g of water should be 0.559 g while in statement it is less i.e. 0.290 g.
The answer is 3.10 because it's still the same amount moles of iron.
Answer:
See the answer below
Explanation:
<em>The correct answer would be that the solute particles lower the solvent's vapor pressure, thus requiring a higher temperature to cause boiling.</em>
Dissolving a solute particle in a solvent leads to a decrease in the vapor pressure of the solvent above the resulting solution when compared to the pure solvent. The lower the vapor pressure of a liquid, the higher the temperature required for the liquid to boil and vice versa. Hence, a higher temperature would be needed to boil a solvent with dissolved solutes.
D. Changes
Hope this helps :)
