First term = 2(1) - 3 = 2 - 3 = -1
Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
Answer:
Step-by-step explanation:
m: y = -2x + 4
n: y = x - 1
l: y = 4
p: x = -4
Answer:
2
Step-by-step explanation:
There are two lines of symmetry and here I list them:
1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).
2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.
A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.
So, we only have 2 symmetry lines.
