All categories

2 years ago

Someone please help this is an exam

Mathematics

1 answer:

DiKsa [7]2 years ago

5 0

Answer:

∠ADC and ∠EDG are vertical angles

You might be interested in

A set of equations is given below:

raketka [301]

The correct answer is A, or x + 1 = 4x + 5. We used the substitution method to replace y with x + 1.

4 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through the points (1, –1) and (3, –7)

Akimi4 [234]

Answer:

y = -3x + 2

Step-by-step explanation:

To find the slope of an equation you can do (y2-y1)/(x2-x1). Plug the values in from the equation and you get (-1+7)/(1-3), or 6/-2. This means the slope is -3. Then you plug the values of y and x into an equation y = -3x + b, and you get -1 = (-3)1 + b. Solve for b. -1 = -3 + b, (add 3 to each side) 2 = b. Then plug b back into your equation and you get y = -3x + 2

6 0

3 years ago

Read 2 more answers

In a survey of 400 people randomly selected it was determined that 22 play soccer. What is the probability that a randomly selec

galben [10]

The answer to this problem is 0.055%
And you get that by doing 22/400

7 0

3 years ago

Clare was solving an equation, but when she checked her answer she saw her solution was incorrect. She knows she made a mistake,

Sholpan [36]

Answer:

12 times 5=60 not 70

Step-by-step explanation:

12(5+2y)=4y-(5-9y

60+24y=4y-5-9y

60+24y=-5y-5

29y+60=-5

29y=-65

y=-65/29 or y= about -2.38

brainliest please

5 0

2 years ago

Read 2 more answers

I need help.. A diameter of a circle has endpoints p(-10, -2) and q(4, 6)

Phoenix [80]

A: The center is the mid point of the diameter. So, the center of the circle will be the midpoint of points P and Q. The coordinates of the midpoint are the averaged coordinates of the endpoints.

So, the x-cooardinate of the center is the average of the x-coordinates of P and Q:

$C_x = \dfrac{P_x+Q_x}{2}=\dfrac{-10+4}{2}=\dfrac{-6}{2}=-3$

Try to do the same thing with the y coordinates, and you'll get the y-coordinate $C_y$ . This first part will be over, because the circle will be point

$C=(C_x,C_y)$

B: The radius is exactly half the diameter. So, we find the length of the diameter, and we divide it by 2. To find the length of the diameter, we use the standard formula for the distance between two points:

$d=\sqrt{(P_x-Q_x)^2+(P_y-Q_y)^2}=\sqrt{(-10-4)^2+(-2-6)^2}=\sqrt{260}=2\sqrt{65}$

Divide this length by 2 and you'll get the radius.

C: At this point, we have both the radius and the coordinates of the center. The equation of the circle depends on these two parameters, and it is

$(x-C_x)^2+(y-C_y)^2=r^2$

Substitute $C_x$ and $C_y$ with the coordinates of the center (found in point A.) and $r$ with the radius (found in point B.) and you'll have the equation of the circle.

6 0

3 years ago