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Talja [164]
3 years ago
9

Jack has 9 quarters, 7 dimes, and 5 nickles. Does he have enough money to buy a box of crayons for $3.25?

Mathematics
2 answers:
velikii [3]3 years ago
8 0
9 quarters, 7 dimes, & 5 nickels
A quarter is $0.25, a dime is $0.10, & a nickel is $0.05
So we just need to multiply the values & then add them up.
9 quarters is $2.25, 7 dimes is $0.70, & 5 nickels are $0.25
When you add them up, the total value of Jack's change is $3.20
He's really close, but Jack doesn't have enough money
Galina-37 [17]3 years ago
6 0
9*25
225=$2.25
$2.25+7*10
295=$2.95
$2.95+5*5
$3.20
Jack does not have enough money to buy a box of crayons
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Which ordered pair makes both inequalities true?
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An ordered pair which makes both inequalities true is (-1, -3).

<h3>What is an ordered pair?</h3>

An ordered pair is a pair of two points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.

Next, we would test the ordered pair with the given system of inequalities in order to determine which is true.

For ordered pair (-3, 5), we have:

y < –x + 1

5 < -(-3) + 1

5 < 3 + 1

5 < 4 (False).

For ordered pair (-2, 2), we have:

y < –x + 1

2 < -(-2) + 1

2 < 2 + 1

2 < 3 (True).

y > x

2 > -2 (True)

For ordered pair (-1, -3), we have:

y < –x + 1

-3 < -(-1) + 1

-3 < 1 + 1

-3 < 2 (True).

y > x

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For ordered pair (0, -1), we have:

y < –x + 1

-(-1) < -(0) + 1

1 < 1

1 < 1 (False).

y > x

-1 > 0 (False)

Read more on inequality here: brainly.com/question/27166555

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3 years ago
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Let ​ f(x)=x+2 ​ and ​ g(x)=2x+1 ​ .
gogolik [260]
<h2>x= 0 and x= 1</h2>

Step-by-step explanation:

Given  g(x) = x+2  and   f(x) = 2^x+1

If f(x) = g(x)

⇔2^x+1 = x+2

⇔2^x= x +1

Only x= 1 and x=0 will be satisfy  the above equation.

If x= 1, it gives             and x=0 gives

2^1= 1+1                       2^0=0+1

⇔2=2                          ⇔1=1

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Dafna1 [17]

Answer:

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Simone has 20 bills. One fifth of the bills are hundreds, 1/4 of them are fifties, 1/10 of them are $20s. The rest of the bills
larisa [96]
If Simone has 20 bills, then:

1/5 of 20 = 4 [hundreds]
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So now we can easily find out she had 9 bills of tens - because 20 - 11 = 9 or because (780 - 690) ÷ 10 = 90 ÷ 10 = 9.
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