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Dmitry [639]
2 years ago
8

3(4x + 2) +2(x-1) please help me with this equation

Mathematics
2 answers:
charle [14.2K]2 years ago
4 0

Answer:

1) Multiply and expand the brackets:

12x + 6 + 2x - 2

2) Combine like terms (combine terms that have an x together, and those that don't together.)

14x + 4

If the question wanted you to simplify the expression, then <u>14x + 4</u> is your answer. However, to solve for x, you could equate the expression to 0, but I'm not too sure of this part.

14x + 4 = 0

14x = - 4

x = - 4/14

x = - 2/7

notsponge [240]2 years ago
3 0

Answer:

14x + 4

Step-by-step explanation:

3(4x+2) + 2(x-1)

Distribute by multiplying into the bracket

=12x + 6 + 2x - 2

Group like terms by adding and subtracting

= 14x + 4

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DaniilM [7]
Tank1+tank2=8x^2+2x-1+7x^2-2x+1

Total=15x^2
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<img src="https://tex.z-dn.net/?f=4x%20%7B%7D%5E%7B2%7D%20%20%2B%2020x%20%2B%2025" id="TexFormula1" title="4x {}^{2} + 20x + 25
BigorU [14]

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

Let's Solve ~

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 20x + 25

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 10x + 10x + 25

\qquad \sf  \dashrightarrow \: 2x(2x + 5) + 5(2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) (2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) {}^{2}

or

\sf{\qquad \sf  \dashrightarrow \: 4x² + 20x + 25 }

\sf{\qquad \sf  \dashrightarrow \: (2x)² + (2 \sdot 2x \sdot 5) + (5)²}

[ it's similar to expression - a² + 2ab + b² that is equal to (a + b)² ]

so, let's use this identity here to factorise :

\sf{\qquad \sf  \dashrightarrow \: (2x + 5)²}

I hope it was helpful ~

3 0
1 year ago
A train travels 220 miles in 4 hours. What is the train's speed in feet per minute?
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7 0
3 years ago
Read 2 more answers
The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
ANTONII [103]

Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

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3 years ago
What is the first ordered pair and the second ordered pair?
Delvig [45]
When x=-5, y=(1/5)*(-5)-1=-2, so the first order pair is (-5,-2)
when y=-1, -1=(1/5)x-1, (1/5)x=0, x=0, so the second ordered pair is (0, -1)
7 0
3 years ago
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