X-1/4x^2+7x+3 divided by 2x^2+4x-6/4x^2+11x+6

Mathematics

1 answer:

Zina [86]3 years ago

8 0

You pretty much just flip the second fraction and factor

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Carl, Gilda, Conroy, and Kyla are the four candidates in a school election. Carl received 1/5 of the votes, Gilda received 5% of

Juliette [100K]

Firstly, we can convert all of the fractions into percentages. To do this, we need to make the denominator of the fraction 100, and whatever we do to the denominator we must also do to the numerator.

5 x 20 = 100
1 x 20 = 20.

So Carl recieves 20/100 or 20% of the votes.

4 x 25 = 100
1 x 15 = 25

So Conroy receives 25/100 or 25% of the votes.

If we add these together and Gilda's 5%, we get 50%. Since there are 100% votes overall, we need to do 100 - 50 = 50.

Kyla receives 50% of the votes.

8 0

3 years ago

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The function h(x) = 1/2 (x+3)2 +2. How is the graph of the h(x) translated from the parent graph of a quadratic function, F(x) =

Natali5045456 [20]

For this case, the parent function is given by:
$F (x) = x ^ 2
$
We apply the following function transformation:
Vertical compressions:
To graph y = a * f (x)
If 0 <a <1, the graph of y = f (x) is compressed vertically by a factor a. (Shrinks)
We have then:
$y = (1/2) * x ^ 2
$
Horizontal translations:
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
We have then:
$y = (1/2) * (x + 3) ^ 2
$
Vertical translations:
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
We have then:
$h (x) = (1/2) * (x + 3) ^ 2 + 2
$
Answer:
Vertical compression by factor of 1/2. Horizontal displacement 3 units to the left. Vertical displacement 2 units up.

3 0

3 years ago

Write the equations in graphing form, then state the vertex of the parabola or the center and radius of the circle.

Sati [7]

All we need is to put this form in the vertex form f(x) = (ax+b)^2 + c

So we have f (x)= 3x^2+12x+11 ....

Let's complete the square (if you aware of it)

f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
= 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3(x+2)^2 - 12 +11 = 3(x+2)^2 -1

so our form would be:

$f(x)=3(x+2)^2-1$

Here is a parabola with vertex of (-2,-1) and with positive slope (concave up)

I hope that helps!

6 0

3 years ago

HELP QUICK PLZ!!!

yulyashka [42]

B. 12 is the answer to your queation

7 0

3 years ago

From the set {0, 1, 15}, use substitution to determine which value of makes the equation true.

DanielleElmas [232]

Answer:

b = 0.

Step-by-step explanation:

The only value for b that makes the equation true is 0. So, the equation has a unique solution of b = 0.

6 0

2 years ago