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Anna007 [38]
3 years ago
11

Write "P (x) = -36x^2 + 900x - 1584" in standard vertex form, help please!

Mathematics
2 answers:
jolli1 [7]3 years ago
8 0

Answer:

y = a(x – h)2 + k, where (h, k) is the vertex;

in our case, P(x) = a Δ/4a ;

a = -36; b = 900; c = -1584;

b/2a = 900/-72 = -12.5;

Δ =  4ac = 810000 - 144*1584 = 581904 => -Δ/4a = 4041;

P(x) = (-36)(x - 12.5)^2 + 4041, where (12.5 , 4041) is the vertex;

Kazeer [188]3 years ago
7 0
<span>y = a(x – h)2 + k</span><span>, where </span><span>(h, k)</span><span> is the vertex;

in our case, P(x) = a</span>(x + b/2a)^{2} - Δ/4a ;

a = -36; b = 900; c = -1584;

b/2a = 900/-72 = -12.5;

Δ = b^{2} - 4ac = 810000 - 144*1584 = 581904 => -Δ/4a = 4041;

P(x) = (-36)(x - 12.5)^2 + 4041, where (12.5 , 4041) is the vertex;


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Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
Find the surface area of the right prism. Round to the nearest whole number.
andriy [413]

Answer:

\large\boxed{S.A.=96\ cm^2}

Step-by-step explanation:

We have:

(1) two trapezoids with bases b₁ = 7cm and b₂ = 5cm and the height h = 4cm

(2) three rectangles 3 cm × 7 cm, 3 cm × 4 cm and 3 cm × 5 cm.

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

Substitute:

A=\dfrac{7+5}{2}\cdot4=24\ cm^2

Calculate the areas of the rectangles:

A_1=(3)(7)=21\ cm^2\\\\A_2=(3)(4)=12\ cm^2\\\\A_3=(3)(5)=15\ cm^2

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