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3 years ago

7

Which of the following is the correct name for the compound MgBr2?

1 answer:

devlian [24]3 years ago

5 0

I believe the answer is B. Magnesium bromide , if I helped..... You're welcome

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If the mass of 23 gummi bears is 49.2g, what is the average mass of one gummi bear? Round answer to the nearest 0.00g (do NOT ty

Mila [183]

just divide the mass 49.2 grams by the amount of gummi bears 23 to get the answer of 2.1391 then it says to round to 2 decimals so 2.14 grams

3 0

3 years ago

What volume of a 5.00M solution of hydrochloric acid contains 8.00mol of HCl?

rjkz [21]

Answer:

520ML and apparently I need to put more in this answer

Explanation:

brainly.com

7 0

3 years ago

Iron(III) oxide and hydrogen react to form iron and water, like this: Fe_2O_3(s) + 3H_2(g) rightarrow 2Fe(s) + 3H_2O(g) At a cer

Sergeeva-Olga [200]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The equilibrium constant is $K_c= 2.8*10^{-4}$

Explanation:

From the question we are told that

The chemical reaction equation is

$Fe_{2} O_{3}_{(s)} + 3H_{2}_{(g)} -----> 2Fe_{(s)} + 3H_{2} O_{(g)}$

The voume of the misture is $V_m = 5.4L$

The molar mass of $Fe_{2} O_{3}_{(s)}$ is a constant with value of $M_{Fe_{2} O_{3}_{(s)} } = 160g/mol$

The molar mass of $H_{2}_{(g)}$ is a constant with value of $H_2 = 2g/mol$

The molar mass of $H_{2}O$ is a constant with value of $H_2O = 18g/mol$

Generally the number of moles is mathematically given as

$No \ of \ moles \ = \frac{mass}{molar\ mass}$

For $Fe_{2} O_{3}_{(s)}$

$No \ of\ moles = \frac{3.54}{160}$

$= 0.022125 \ mols$

For $H_{2}$

$No \ of\ moles = \frac{3.63}{2}$

$= 1.815 \ mols$

For $H_{2}O$

$No \ of\ moles = \frac{2.13}{18}$

$= 0.12 \ mols$

Generally the concentration of a compound is mathematicallyrepresented as

$Concentration = \frac{No \ of \ moles }{Volume }$

For $Fe_{2} O_{3}_{(s)}$

$Concentration[Fe_2 O_3] = \frac{0.222125}{5.4}$

$= 4.10*10^{-3}M$

For $H_{2}$

$Concentration[H_2] = \frac{1.815}{5.4}$

$= 0.336M$

For $H_{2}O$

$Concentration [H_2O] = \frac{0.12}{5.4}$

$= 0.022M$

The equilibrium constant is mathematically represented as

$K_c = \frac{[concentration \ of \ product]}{[concentration \ of \ reactant ]}$

Considering $H_2O \ for \ product$

And $H_2 \ for \ reactant$

At equilibrium the

$K_c = \frac{0.022}{0.336}$

$K_c= 2.8*10^{-4}$

3 0

3 years ago

P 4 + 5O 2 P 4 O 10 , 1.5 moles of product was made in 30 seconds. What is the rate of reaction? 0.011 g/min 210 g/min 380 g/min

Airida [17]

Answer: 850.0 g/min.

Explanation:

The rate of the reaction = (ΔC/Δt) where,

ΔC is the change in concentration of reactants or products.

Δt is the change in time of the reaction proceeding.

The rate is needed to be calculated in (g/min).

We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).

mass (g) = n x molar mass,

n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.

m = 1.5 x 283.88 = 425.82 g.

ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.

The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.

<em>can be approximated to 850.0 g/min.</em>

6 0

3 years ago

Read 2 more answers

Please answer by the number ! I will mark any correct answer brainliest :)

jeyben [28]

Answer:

36 joules is the answer

1/2mv^2

1/2* 8*3*3

4*9

36joules

5 0

2 years ago