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natta225 [31]
4 years ago
7

Which of the following is the correct name for the compound MgBr2?

Chemistry
1 answer:
devlian [24]4 years ago
5 0
I believe the answer is B. Magnesium bromide , if I helped..... You're welcome
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Provide at least three indicators of a chemical change that are present in burning a piece of paper.
Pie

Answer:

Some chemical indicators perceived while a piece of paper is burning are:

Production of an Odor: there is a smell of burnt paper

Change in Temperature:  combustion is a highly exothermic reaction , so the temperature increase

Change in Color: paper changes to ashes as the burning process occurs

3 0
3 years ago
Determine the number of ions produced in the dissociation of the compound listed. BaS
11Alexandr11 [23.1K]
BaS → Ba²⁺ + S²⁻
two types of ions
4 0
4 years ago
Read 2 more answers
The cube has a mass of 72.9 g.<br><br> What is its density in g/cm3? <br><br> What substance is it?
sashaice [31]
If the cube is 3 cm on each side, then it has a volume of 27 cm^3 (3 x 3 x 3). Density is mass divided by volume, so its density is 72.9/27 = 2.7 g/cm^3. 

<span>Going by the density, the cube is made of Aluminium - density is a fairly unique quantity</span>
6 0
3 years ago
Is methylene chloride more or less dense than water?
horsena [70]
Methylene chloride is less dense than water
3 0
3 years ago
If the percent yield for the following reaction is 75.0%, and 25.0 g of NO₂ are consumed in the reaction, how many grams of nitr
victus00 [196]

Answer:

17.1195 grams of nitric acid are produced.

Explanation:

3NO_2+H_2O\rightarrow 2HNO_3+NO

Moles of nitrogen dioxide :

\frac{25.0 g}{56 g/mol}=0.5434 mol

According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.

Then 0.5434 moles of nitrogen dioxides will give:

\frac{2}{3}\times 0.5434 mol=0.3623 mol of nitric acid.

Mass of 0.3623 moles of nitric acid :

0.3623 mol\times 63 g/mol=22.8260 g

Theoretical yield = 22.8260 g

Experimental yield = ?

\%Yield=\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100

75\%=\frac{\text{Experimental yield}}{22.8260 g}

Experimental yield of nitric acid = 17.1195 g

7 0
3 years ago
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