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s2008m [1.1K]
3 years ago
6

Forests are the only carbon sinks on Earth. Please select the best answer from the choices provided T F

Chemistry
2 answers:
STALIN [3.7K]3 years ago
8 0

Answer: True

Forests are natural reserves on earth. They exhibit large population of fauna and flora. The floral community is responsible for maintaining the climate of the environment. The plants and trees absorbs the atmospheric carbon dioxide, to utilize it as a reactant of the photosynthesis process. Carbon dioxide being a potent greenhouse gas exhibit role in increasing the global temperature, and mainly responsible for global warming. Forests can reduce this impact and acts as carbon sink on earth.

Therefore, the statement "Forests are the only carbon sinks on Earth." is true.

dmitriy555 [2]3 years ago
4 0
False, as oceans can act as carbon sinks along with forests. 
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How many moles are in 7.8g of CaO?
Bess [88]

This compound is also known as Calcium Oxide. The SI base unit for amount of substance is the mole. 1 grams CaO is equal to 0.017832495800447 mole. Note that rounding errors may occur, so always check the results.

Hope I helped :)

4 0
3 years ago
Calculate the empirical formula for each stimulant based on its elemental mass percent composition. a. nicotine (found in tobacc
Ira Lisetskai [31]

This an incomplete question, here is a complete question.

Calculate the empirical formula for each stimulant based on its elemental mass percent composition.

a. nicotine (found in tobacco leaves): C 74.03%, H 8.70%, N 17.27%

b. caffeine (found in coffee beans): C 49.48%, H 5.19 %, N 28.85% and O 16.48%

Answer:

(a) The empirical formula for the given compound is C_5H_7N

(b) The empirical formula for the given compound is C_4H_5N_2O

Explanation:

<u>Part A: nicotine </u>

We are given:

Percentage of C = 74.03 %

Percentage of H = 8.70 %

Percentage of N = 17.27 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 74.03 g

Mass of H = 8.70 g

Mass of N = 17.27 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{74.03g}{12g/mole}=6.17moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{8.70g}{1g/mole}=8.70moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{17.27g}{14g/mole}=1.23moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.23 moles.

For Carbon = \frac{6.17}{1.23}=5.01\approx 5

For Hydrogen  = \frac{8.70}{1.23}=7.07\approx 7

For Nitrogen = \frac{1.23}{1.23}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

The empirical formula for the given compound is C_5H_7N_1=C_5H_7N

<u>Part B: caffeine</u>

We are given:

Percentage of C = 49.48 %

Percentage of H = 5.19 %

Percentage of N = 28.85 %

Percentage of O = 16.48 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 49.48 g

Mass of H = 5.19 g

Mass of N = 28.85 g

Mass of O = 16.48 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{49.48g}{12g/mole}=4.12moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{5.19g}{1g/mole}=5.19moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{28.85g}{14g/mole}=2.06moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{16.48g}{16g/mole}=1.03moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.03 moles.

For Carbon = \frac{4.12}{1.03}=4

For Hydrogen  = \frac{5.19}{1.03}=5.03\approx 5

For Nitrogen = \frac{2.06}{1.03}=2

For Nitrogen = \frac{1.03}{1.03}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N : O = 4 : 5 : 2 : 1

The empirical formula for the given compound is C_4H_5N_2O_1=C_4H_5N_2O

6 0
3 years ago
1.34 milligrams is the same as _____ kg and _____g.
Karolina [17]
Answer C is for kg and but it's .00134 for grams
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Is it possible to use subatomic particles as an energy source?
Alex17521 [72]

Yes, Is it possible to use subatomic particles as an energy source.

<h3>What are subatomic particles?</h3>

A subatomic particle is nothing but a particle which is smaller than an atom in size. Typically, an atom can be broken down into three subatomic particles, namely: protons, electrons, and neutrons.

Yes, Is it possible to use subatomic particles as an energy source.

There are instances when the protons and electrons in an atom's outermost shells are not strongly attracted to one another. It is possible to force these electrons out of their orbits.

They may move from one atom to another by exerting force. Electricity is made up of these moving electrons.

Learn more about subatomic particles here:

brainly.com/question/13303285

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8 0
2 years ago
The partial charges in this water molecule occur because of _____.
Step2247 [10]
The answer will be because of the unequal sharing of electrons between the hydrogen and the oxygen atoms of a water molecule.

Hope this helps.

I'd appreciate brainliest answer from u please.
5 0
3 years ago
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