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2 years ago

How many molecules are 0.5000 miles of H2?

1 answer:

4 0

1 mol of wager contains 6.002 * 1023 H2O molecules. Therefore, 0.500 mol contains 0.5000 * (6.022*1023)=3.01*1023 H2O molecules.

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Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you

oee [108]

Answer:

The mass of oxygen is 12.10 g.

Explanation:

The decomposition reaction of potassium chlorate is the following:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

We need to find the number of moles of KClO₃:

$\eta_{KClO_{3}} = \frac{m}{M}$

Where:

m: is the mass = 30.86 g

M: is the molar mass = 122.55 g/mol

$\eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles$

Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3

$\eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles$

Finally, the mass of O₂ is:

$m = 0.378 moles*32 g/mol = 12.10 g$

Therefore, the mass of oxygen is 12.10 g.

I hope it helps you!

6 0

2 years ago

A stable atom that has a large nucleus most likely contains

Gre4nikov [31]

Most atoms have more neutrons than protons which accounts for basically half of the nucleuses mass.

7 0

3 years ago

Read 2 more answers

How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with

konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = $a=31 cm^2$

Thickness of the gold plating = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

$V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3$

Density of the gold = $d=19.3 g/cm^3$

$m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g$

Moles of gold = $\frac{29.915 g}{197 g/mol}=0.152 mol$

$Au^{3+}+3e^-\rightarrow Au$

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

$\frac{3}{1}\times 0.152 mol=0.456 mol$ of electrons

Number of electrons = N = $0.456\times \times 6.022\times 10^{23}$

Charge on single electron = $q=1.6\times 10^{-19} C$

Total charge required = Q

$Q=N\times q$

Amount of current passes = I = 8 Ampere

Duration of time = T

$I=\frac{Q}{T}$

$T=\frac{N\times q}{I}$

$=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s$

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0

2 years ago

How many bonds are present in Cl20?<br> a. 2<br> b. 4<br> c. 1<br> d. 3

steposvetlana [31]

Answer:

A. 2 bonds

Explanation:

If you see a charch of ci20 it would easily show the answer.

8 0

2 years ago

Matter is made up of heat energy and ___________energy?

ella [17]

You’re correct, matter is made up of heat energy and chemical energy

all matter contains heat because it is the result of the movement of atoms, molecules, or ions in solids, liquids, and gases.

all matter also contains chemical energy. chemical energy is stored in the bonds of chemical compounds so atoms and molecules are held together by chemical energy

hope this helps :)

3 0

2 years ago