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Furkat [3]
3 years ago
14

Verify the identity cos ( x + pi/2) = -sin x

Mathematics
2 answers:
Citrus2011 [14]3 years ago
6 0

Answer:

cos(x+\frac{\pi}{2} )=-sin(x)

The identity is true

Step-by-step explanation:

This can be verified using multiple methods, for example you can use graphical methods if you know the exact form of the cosine function and the sine function. However, in this case, we are going to use a very useful identity, which is the cosine sum identity. This identity is given by the following equation:

cos(\alpha + \beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)

In this case:

\alpha=x\\\beta=\frac{\pi}{2}

So:

cos(x+\frac{\pi}{2} )=cos(x)cos(\frac{\pi}{2})-sin(x)sin(\frac{\pi}{2})

Where:

cos(\frac{\pi}{2})=0\\\\And\\\\sin(\frac{\pi}{2})=1

Therefore:

cos(x+\frac{\pi}{2} )=cos(x)(0)-sin(x)(1)\\\\cos(x+\frac{\pi}{2} )=-sin(x)

IgorLugansk [536]3 years ago
3 0
Hello 
cos ( x + pi/2) =cos(x)cos(pi/2)-sin(x) sin(pi/2) 
                       = cos(x)×0-sin(x) ×1
                    cos ( x + pi/2)   = - sin(x)
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The equation that is equivalent to S=pi r^2 h is h = S/pir^2

<h3>Subject of formula</h3>

This is a way of representing a variable with another. Given the equation

S=pi r^2 h

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