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3 years ago

8

2/3 of the cards are pitchers and 3/4 of the remainder are outfielders. If the 3 cards left over are infielders, how many cards

does Jordan have?

1 answer:

snow_tiger [21]3 years ago

6 0

Answer:

2/3 + 3/4 = 1 52/125. That plus 3 is 4 / 52/125. Sorry if this isn't the right answer.

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A box of 15 cookies costs $9. What is the cost for 1 cookie?

Volgvan

Let's set up a proportion. (<em>We will call our answer x.</em>)

15 cookies / 9 dollars = 1 cookie / x dollars
15x = 9
x = 9/15 dollars

x = 60 cents

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9 students at a math club picnic if 6 students are drinking punch and 3 are drinking lemonade what fraction are drinking punch

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Answer:

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Step-by-step explanation:

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3 years ago

Find (f•g)(x) when f(x)=sqrt x+3/x and g(x)=sqrt x+3/2x

elena-14-01-66 [18.8K]

For multiplying radical expressions, we are first to list down the given.
f(x) = (x + 3/x)^(1/2), and
g(x) = (x + 3/2x)^(1/2)

We take a look at first the values of the radicands, these are the numbers inside the radical signs. Since, both of the radicands are raised to exponent 1/2, it is easy to say that we just have to multiply them and raise the product to the exponent 1/2 as well. That is,

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Further simplification will lead us to the final answer of,
<em>(f·g)(x) = (x² + 9/2 + 9/2x²)^(1/2)</em>

3 0

3 years ago

On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl

kondor19780726 [428]

Answer:

0.40

Step-by-step explanation:

Members who run only long distance = 8%

So, probability that a member will run only long distance = P(A) = 0.08

Members who compete only in field events = 32%

So, probability that a member will compete only in field events = P(B) 0.32

Members who are sprinters = 12%

So, probability that a member is sprinter = P(C) 0.12

We have to calculate the probability that a randomly chosen team member runs only long-distance or competes only in field events. i.e we have to find P(A or B). Since these events cannot occur at the same time, we can write:

P(A or B) = P(A) + P(B)

Using the values, we get:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the probability that a randomly chosen team member runs only long-distance or competes only in field events is 0.40

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3 years ago