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3 years ago

Let f(x) = x - 1/x. which of the following are zeros of f(x)?

1 answer:

7 0

I'm assuming that is f(x) = (x-1)/x
In that case, the answer would be just x = 1.

However, if the original is f(x) = x - (1/x) the answer would be x = 1 and x = -1.

It's really just a formatting thing—if the given equation is indeed f(x) = (x-1)/x then x = 1 is the answer.

Hope this helped!! xx

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First to get it right gets brainliest

777dan777 [17]

Answer:

C. r = d/2

Step-by-step explanation:

The radius is half of the diameter.

The diameter divided by 2 would equal the radius of a circle.

7 0

2 years ago

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Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.

3 0

3 years ago

an airplaine descends 1.5 miles to an elevation of 5.25 miles. find the elevation of the plane before its descent

Maksim231197 [3]

We can then write an equation representing this problem as:

e−1.5mi=5.25mi

Now, add 1.5mi to each side of the equation to solve for e while keeping the equation balanced:

e−1.5mi+1.5mi=5.25mi+1.5mi

e−0=6.75mi

e=6.75mi

The plane's starting elevation was 6.75 miles

Hope this helps!

8 0

3 years ago

Evaluate M^2/P^4 for M = 10, N = -5, and P = -2

castortr0y [4]

10^2/-2^4

100/16=6.25

3 0

3 years ago

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The scale of a map is 1:4 000 000. Hint: 1:4 000 000 means that 1cm on the map = 4 000 000 on the ground. The distance between L

GrogVix [38]

Answer:

325 km

Step-by-step explanation:

Given the scale :

1 : 4 ,000, 000

1cm measure in map = 4000000 on the ground

From the map :

Distance between Leeds and London = 8.125 cm

The actual distance on ground can be calculated thus :

1cm = 4,000,000

8.125cm = x

Cross multiply

x = 32500000 cm

Converting to kilometers :

1 km = 100,000 cm

x = 32500000

Cross multiply

100,000x = 32500000

x = 32500000 / 100000

x = 325

Hence, actual distance between Leeds and London is 325 km

3 0

2 years ago