A and B are right C is incenter D is totally wrong hope this helps god bless
The length of one of the legs of an isosceles right triangle and has a hypotenuse length of seven times the square root of two is 7 units.
<h3>What is an Isosceles triangle?</h3>
Isosceles triangles are triangles that has two of it sides equal to each other. The base angles of an isosceles triangle are equal.
The isosceles triangle is also a right angle triangle. The hypotenuse is the longest side of a right angle triangle.
Therefore,
hypotenuse = 7(√2)
let the length of the other legs = x
Therefore, using Pythagoras theorem
c² = a² + b²
(7(√2))² = x² + x²
49 × 2 = 2x²
98 = 2x²
x² = 98 / 2
x = √49
x = 7 units
learn more on isosceles triangle here: brainly.com/question/10412877
There you go hope that’s helps !!!
Start with the second expression. That factors easily into (8x-3)(8x+3).
Since 64x^2 + 48x + 9 has no negative signs, I'd bet that the common factor is (8x+3). Divide <span>64x^2 + 48x + 9 by that to verify.
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For finding x:
We want to use tangent because tangent is opposite/adjacent
tan (30)= x/15
Multiply both sides of the equation by 15 to isolate x
Now we have, (15)(tan 30) = x
Simply plug the above equation into your calculator and you should get x=8.66
For y:
We know the angle opposite side y is= 90˚ (it is marked as a right angle)
We are going to use cosine because cosine is adjacent/hypotenuse
So, cos(90)= 15/y
Multiply by y
(y)(cos 90)=15
Now use simple algebra
cos (90) = 0
Y x 0 =15
y=15
Hope this helps. By the way, I am a little rusty on this topic so I am not 100% sure that this is right (I'm 98% sure).
