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Andrej [43]
3 years ago
8

Following solutions to this equation?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

Step-by-step explanation:

hello :

x²+6x+9 = 20

(x+3)²-20 = 0

(x+3)²-√20 = 0

(x+3-√20)(x+3+√20)=0

x+3-√20=0   or    x+3+√20=0

x = -3+√20   or x = -3-√20    answer  B

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A tree with a height of 4 ft casts a shadow 15ft long on the ground how tall is another tree that cast a shadow which is 20ft lo
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Height of another tree that cast a shadow which is 20ft long is 5 feet approximately

<h3><u>Solution:</u></h3>

Given that tree with a height of 4 ft casts a shadow 15ft long on the ground

Another tree that cast a shadow which is 20ft long

<em><u>To find: height of another tree</u></em>

We can solve this by setting up a ratio comparing the height of the tree to the height of the another tree and shadow of the tree to the shadow of the another tree

\frac{\text {height of tree}}{\text {length of shadow}}

Let us assume,

Height of tree = H_t = 4 feet

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Set up a proportion comparing the height of each object to the length of the shadow,

\frac{\text {height of tree}}{\text {length of shadow of tree}}=\frac{\text { height of another tree }}{\text { length of shadow of another tree }}

\frac{H_{t}}{L_{t}}=\frac{H_{a}}{L_{a}}

Substituting the values we get,

\frac{4}{15} = \frac{H_a}{20}\\\\H_a = \frac{4}{15} \times 20\\\\H_a = 5.33

So the height of another tree is 5 feet approximately

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