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2 years ago

Samantha works at a nursery, where she pots plants. it takes her 1 1/2 hours to pot 12 plants.

Mathematics

1 answer:

nignag [31]2 years ago

4 0

Answer:

She could plant 9 plants.

Step-by-step explanation:

1 1/2 hours = 90 minutes, so 12 plants per 90 minutes. Which would mean 6 plants per 45 minutes. So in between 45 and 90 minutes (1 hour), and in between 6 and 12 plants (9).

Sorry if you didn't understand, I'm bad at explaining.

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What is the slope / rate of change for 2, 5 and -3, 7

Nady [450]

Answer:

$\displaystyle m=\frac{-2}{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS 

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (2, 5)

Point (-3, 7)

Step 2: Identify

x₁ = 2, y₁ = 5

x₂ = -3, y₂ = 7

Step 3: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m=\frac{7-5}{-3-2}$
[Slope] [Fraction] Subtract: $\displaystyle m=\frac{2}{-5}$
[Slope] [Fraction] Rewrite: $\displaystyle m=\frac{-2}{5}$

4 0

3 years ago

What is the mean of 65,30,25

mixas84 [53]

You've got 3 values there.

Get the sum of 65, 30 and 25 and divide their sum by the number of values that exist, which in this case is 3.

$\frac { 65+30+25 }{ 3 } =\frac { 120 }{ 3 } =40$

Answer:

40

5 0

3 years ago

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What is the answer Simplify. 1/4(1-2/3 squared+1/3

NemiM [27]

The Answer is 2/3

Steps: 1/4(1-(2/3^2+1/3)

3 0

3 years ago

Which type of transformation is shown below?

Lina20 [59]

Answer:

C.) A dilation. It got bigger so its a dilation

7 0

2 years ago

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!! AP CALCULUS AB !! find the limit of [(secx*sinx) + (cscx*cosx)]/(3secx) as x approaches 3pi/2

uysha [10]

$f(x)= \frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}}$

$\frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}} \implies \\ \frac{\sin^2{x}+\cos^2{x}}{\sin{x}\cos{x}}\frac{\cos{x}}{3}\implies \\\frac{1}{\sin{x}\cos{x}}*\frac{\cos{x}}{3}\implies \\ \frac{1}{3\sin{x}}$

So,

$\lim_{x \rightarrow \frac{3\pi}{2}}{f(x)=f(\frac{3\pi}{2})=\frac{1}{3\sin{\frac{3\pi}{2}}}=-\frac{1}{3}$

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3 years ago