All categories

3 years ago

In this geometric sequence, what is the common ratio?

Mathematics

2 answers:

Lapatulllka [165]3 years ago

6 0

Answer:-1/2

Step-by-step explanation:

common ratio=(2nd term➗Ist term) or (3rd term➗2nd term)

first term=104

Second term=-52

Common ratio=-52 ➗ 104

Common ratio=-1/2

mrs_skeptik [129]3 years ago

4 0

Answer:

-2

Step-by-step explanation:

Each value is divided by -2 to get to the next term

You might be interested in

Find the rate of change in table plsss helppp!!!!

KonstantinChe [14]

Answer:

it changes by 4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please answer !!!the system of equations graphed below has how many solutions ?

OverLord2011 [107]

The number of intersections is the number of solutions

we can see they are paralell so they will never intersect
0

C is the answer

5 0

3 years ago

Read 2 more answers

When a product of integers has an odd number of negative factors, then sign of the product is?

Phoenix [80]

Answer:

<em>The product of an even number of negatives give us a positive number. An odd number of - 1's gives us a negative one, -1. This can be applied to any set of products. The product of an odd number of negatives give us a negative number. </em>

Step-by-step explanation:

4 0

3 years ago

What are the answers to a, b, c, d?

Nezavi [6.7K]

Answer:

Step-by-step explanation:

8 0

3 years ago

From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?

Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

$P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}$

$P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}$

$P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}$

The expected number of men in the delegation is

$E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)$

$E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}$

$E(x)=\dfrac{6}{7}$

$E(x)\approx 0.86$

Therefore, the expected number of men in the delegation is 0.86.

4 0

3 years ago