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zlopas [31]
3 years ago
5

How many solutions are there to the quadratic equation

Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0

Answer:

2

Step-by-step explanation:

(-7)^2  -  4*3 *(-2) =   49 + 24  >0

discriminant is positive so 2 real roots

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(08.05)
Crank
If you use the first answer, the equation becomes 2x + 2y = 16.  You could subtract this from equation Q to eliminate x.

The second answer makes equation P -2x - 2y = -16.  You could add this to equation Q to eliminate x.  You can use both of these methods to eliminate the x term, but if you can only choose one, you should choose the second option.
7 0
3 years ago
Read 2 more answers
X≥1 x≤7 y≥-1/3x+6
Goshia [24]

Answer:

Step-by-step explanation:

i am unsure of what you actually need, but i want to help you.

if you were to set the boundaries of the feasibility region it would be as follows:

as points

A(1, 17/3)   B(7, 11/3)   C(7, infinity)   D(1, infinity)

as graphs

y=-1/3x+6 where 1≤x≤7

x=1

x=7

7 0
3 years ago
Read 2 more answers
Simplify 4^2 * 4^8= A.)4^16 B.)4^10 C.)16^16 D.)16^10 please help me i need this asap.
SVEN [57.7K]

Answer:

4^{10}

Step-by-step explanation:

Complete the exponents first.

4*4=16

4*4*4*4*4*4*4*4=65536

65536 *16= 1048576

The answer is 4^{10}

You can also find this if you add the exponents.

6 0
3 years ago
One week Michael worked 40 hours and sold 2,870 worth of shoes if his employer paid him 12.50 per hour and 6% commission of all
liq [111]

Answer:

Money which Michael make in commission = 158.7

Step-by-step explanation:

Given that,

number of hours Michael worked in a week = 40 hours

total sale of the week = 2870

commission which Micheal will get on sale = 6% above 225sale

To find,

total money Michael make in commission in the week

Commission = (2870 - 225)*6%

Commission = (2870 - 225)*6/100

Commission = 2645 *6/100

Commission = 158.7

Total money Micheal make in a week = (40*12.50) + (158.7)

                                                                 = 658.7

5 0
3 years ago
Which point would be a solution to the system of linear inequalities ?
brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

y\leq \frac{4}{3}x+5 ----> inequality A

y\geq -\frac{5}{2}x+5 ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y  of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

-1\leq \frac{4}{3}(0)+5

-1\leq5 ----> is true

Inequality B

-1\geq -\frac{5}{2}(0)+5

-1\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

3\leq \frac{4}{3}(0)+5

3\leq5 ----> is true

Inequality B

3\geq -\frac{5}{2}(0)+5

3\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

-6\leq \frac{4}{3}(-6)+5

-6\leq-3 ----> is true

Inequality B

-6\geq -\frac{5}{2}(-6)+5

-6\geq 20----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

-6\leq \frac{4}{3}(12)+5

-6\leq21 ----> is true

Inequality B

-6\geq -\frac{5}{2}(12)+5

-6\geq -25 ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0
3 years ago
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