Alliteration because pours and potions both have p's (i'm pretty sure)
5.2x10^6 is the right answer because the decimal is moved 6 times to the right which makes the 5 the first number because it can’t be more than 10
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Find Length of the square :
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Given that the area of the square is 32 cm²:
Area = Length²
![\text {Length =} \sqrt{32}](https://tex.z-dn.net/?f=%5Ctext%20%7BLength%20%3D%7D%20%20%5Csqrt%7B32%7D%20)
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Find Radius :
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Using Pythagorus Theorem to find the radius of the circle:
a² + b² = c²
![( \sqrt{32})^2 + (\frac{ \sqrt{32} }{2} )^2 = ( \text {radius} )^2](https://tex.z-dn.net/?f=%28%20%5Csqrt%7B32%7D%29%5E2%20%2B%20%28%5Cfrac%7B%20%5Csqrt%7B32%7D%20%7D%7B2%7D%20%29%5E2%20%3D%20%28%20%5Ctext%20%7Bradius%7D%20%29%5E2)
![(\text {radius} )^2 = 32 + \dfrac{32}{4}](https://tex.z-dn.net/?f=%28%5Ctext%20%7Bradius%7D%20%29%5E2%20%3D%2032%20%2B%20%5Cdfrac%7B32%7D%7B4%7D%20)
![(\text {radius} )^2 = 40](https://tex.z-dn.net/?f=%28%5Ctext%20%7Bradius%7D%20%29%5E2%20%3D%2040)
![\text { Radius = } \sqrt{ 40 }](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Radius%20%3D%20%7D%20%20%5Csqrt%7B%2040%20%7D%20)
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Find Area of the semi-circle :
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![\text {Area of the semi-circle = } \dfrac{1}{2} \pi r^2](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20the%20semi-circle%20%3D%20%7D%20%20%20%5Cdfrac%7B1%7D%7B2%7D%20%5Cpi%20r%5E2)
![\text {Area of the semi-circle = } \dfrac{1}{2} \pi ( \sqrt{40}) ^2](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20the%20semi-circle%20%3D%20%7D%20%5Cdfrac%7B1%7D%7B2%7D%20%5Cpi%20%28%20%5Csqrt%7B40%7D%29%20%5E2)
![\text {Area of the semi-circle = } 20 \pi](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20the%20semi-circle%20%3D%20%7D%2020%20%5Cpi%20)
Answer:
1,2,5
Step-by-step explanation:
Failed on EDG
Answer:
m= rise of the bank balance over/the increase of time y= is your bank balance x=is the time in weeks b= is your y-intercept when x=0
Step-by-step explanation:
To write the equation use y-intercept formula which is y=mx+b