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shepuryov [24]
3 years ago
8

If you mix 1 cup of chocolate chips and 1 cup of raisins what is the percentage of chocolate chips

Mathematics
1 answer:
algol133 years ago
4 0

Answer:

50%

Step-by-step explanation:

50% because when there is only 2 variables and they are each 1 cup there is an even amount of stuff and when you ask for only one percentage that would be 50% because everything is even. Even if you asked for the percentage for the cup of raisins it would also be 50%. Hope this helps <3

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How do you solve y=2x+7; 3x-y=-9 using substitution method. Explain please!!
eduard
The y's value is given in the first equation. y=2x+7 . Now to solve, we will, plug it's value in the second equation.

3x-(2x+7)=-9\\ \\ 3x-2x-7=-9\\ \\ x=-9+7\\ x=-2\\

Now we have x's value, we will plug it's value in the first equation.(We can plug it in the second one too, but plugging it the first one will make it easier.)

x=-2\\ y=2x+7\\ y=2\cdot -2+7\\ y=-4+7\\ y=3




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Step-by-step explanation:

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Tems11 [23]

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A box contains 2 blue markers, 5 green markers and 3 yellow markers. What is the probability of drawing a blue marker, replacing
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8 0
3 years ago
4. If 100.0g of nitrogen gas (N2) is reacted with 100.0g of hydrogen gas (H2) to form NH3. What are the limiting and excess reac
alexandr1967 [171]

Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have

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Hydrogen (H) has a molar mass of about 1.008 g/mol, so

100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂

In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have

3.570 • 3 ≈ 10.71

so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.

(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.

(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.

(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or

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