Ways of choosing 3 course meal 5*10*4=200 Ways of choosing 2 course meal (5*10)+(5*4)+(10*4)=110 Ways of choosing 1 course meal 5+10+4=19
possible ways of choosing at least 1 option: =(ways of choosing 3 course meal)+(ways of choosing 2 course meal)+(ways of choosing 1 course meal)= 200+110+19=329
329 combinations.
I think the answer would be 4^4
Because 9-5 =4 not sure though
Answer:
The width is 4 cm
Step-by-step explanation:
12.5 x 4.5 = 56.25
225 ÷ 56.25 = 4
Width = 4 cm
$5 for reg
$10 for mid
$15-$20 for loud
Part a)
It was given that 3% of patients gained weight as a side effect.
This means


The mean is


The standard deviation is



We want to find the probability that exactly 24 patients will gain weight as side effect.
P(X=24)
We apply the Continuity Correction Factor(CCF)
P(24-0.5<X<24+0.5)=P(23.5<X<24.5)
We convert to z-scores.

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.
P(X≤24)
We apply the continuity correction factor to get;
P(X<24+0.5)=P(X<24.5)
We convert to z-scores to get:

Part c)
We want to find the probability that
11 or more patients will gain weight as a side effect.
P(X≥11)
Apply correction factor to get:
P(X>11-0.5)=P(X>10.5)
We convert to z-scores:


Part d)
We want to find the probability that:
between 24 and 28, inclusive, will gain weight as a side effect.
P(24≤X≤28)=
P(23.5≤X≤28.5)
Convert to z-scores:
