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Mama L [17]
3 years ago
5

Consider a supersonic missile flying at Mach 2.5 at an altitude of 10 km. Assume that the angle of the shock wave from the nose

is approximated by the Mach angle (this is a very weak shock). How far behind the nose of the vehicle will the shock wave impinge upon the ground

Physics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

The distance at which nose of the vehicle will the shock wave impinge upon the ground is approximately 23km

Explanation:

Let

u be Mach angle

M be Mach Number = 2.5

h be altitude = 10km

d be distance between nose of the vehicle with which the shock wave impinge upon the ground

Using;

Sin u = 1/M

u = arcSin (1/M)

u = arcSin (1/2.5) = 23.58°

Using angle at a point rule = 90°

90 - 23.58 = 66.42°

Tan A = opp/adj

Tan 66.42° = d/10

2.2911 * 10 = d

d = 22.911km ≈ 23km

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A 15g bullet is fired horizontally into a 3kg block of wood suspended by a long cord. Assume that the bullet remains in the bloc
Varvara68 [4.7K]

Answer:

261.3 m/s

Explanation:

Mass of bullet=m=15 g=\frac{15}{1000}=0.015 kg

1 kg=1000g

Mass of block=M=3 kg

d=0.086 m

Total mass =M+m=3+0.015=3.015 kg

K.E at the time strike=Gravitational potential energy at the end of swing

\frac{1}{2}(m+M)^2V^2=(m+M)gh

Using g=9.8m/s^2

Substitute the values

\frac{1}{2}(3.015)V^2=3.015\times 9.8\times 0.086

V^2=\frac{2\times 3.015\times 9.8\times 0.086}{3.015}

V=\sqrt{2\times 3.015\times 9.8\times 0.086}}

V=1.3m/s

Velocity after collision=V=1.3 m/s

Velocity of block=v'=0

Using conservation law of momentum

mv+Mv'=(m+M)V

Using the formula

0.015v+3(0)=3.015(1.3)

0.015v=3.015(1.3)

v^2=\frac{3.015(1.3)}{0.015}=261.3

v=261.3 m/s

5 0
4 years ago
7. A child of mass m starts from rest and slides without friction from a height h along a curved waterslide (Fig. P5.46). She is
marissa [1.9K]

The mechanical energy of the girl will be conserved because the system is isolated and the initial potential energy will be equal to final kinetic energy.

<h3>What is the law of conservation of energy?</h3>

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

The change in the potential energy of the  launched from a height into the pool without friction from the given height h is calculated by applying the following kinematic equation.

ΔP.E = ΔK.E

where;

  • ΔP.E is change in potential energy of the child
  • ΔK.E is change in the kinetic energy of the child

mghf - mghi = ¹/₂mv²  - ¹/₂mu²

where;

  • m is the mass of the girl
  • g is acceleration due to gravity
  • hi is the initial height of the girl
  • hf is the final height when she is launched into the pool
  • u is the initial velocity
  • v is the final velocity of the girl

Thus, for every closed or isolated system such as this case, mechanical energy is always conserved because the initial potential energy of the girl will be converted into her final kinetic energy.

Learn more about conservation of mechanical energy here: brainly.com/question/332163

#SPJ1

4 0
1 year ago
The work output of a machine divided by the work input is the ____ of the machine.
s344n2d4d5 [400]
<span>The work output of a machine divided by the work input is the "Efficiency" of the machine.

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7 0
4 years ago
A car is initially moving at 10.5 m/s and accelerates uniformly to reach a speed of 21.7 m/s in 4.34 s. How far did the car move
Zarrin [17]

Answer:

A. 69.9m

Explanation:

Given parameters:

Initial velocity = 10.5m/s

Final velocity  = 21.7m/s

Time  = 4.34s

Unknown:

Distance traveled = ?

Solution:

Let us first find the acceleration of the car;

  Acceleration  = \frac{v - u}{t}

  v is final velocity

   u is initial velocity

   t is the time

     Acceleration  = \frac{21.7 - 10.5}{4.34}   = 2.58m/s²

Distance traveled;

     V² = U² + 2aS

    21.7² = 10.5² + 2 x 2.58 x S

   360.64 = 2 x 2.58 x S

     S = 69.9m

3 0
4 years ago
Suppose that a white dwarf is gaining mass through accretion in a binary system. what happens if the mass someday reaches the 1.
Soloha48 [4]
It would blow up turning into a supernova.
7 0
4 years ago
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