Incomplete question as the angle between the force is not given I assumed angle of 55°.The complete question is here
Two forces, a vertical force of 22 lb and another of 16 lb, act on the same object. The angle between these forces is 55°. Find the magnitude and direction angle from the positive x-axis of the resultant force that acts on the object. (Round to one decimal places.)
Answer:
Resultant Force=33.8 lb
Angle=67.2°
Explanation:
Given data
Fa=22 lb
Fb=16 lb
Θ=55⁰
To find
(i) Resultant Force F
(ii)Angle α
Solution
First we need to represent the forces in vector form

Total Force

The Resultant Force is given as

For(ii) angle
We can find the angle bu using tanα=y/x
So

From the theory we know that:
c = λ / T
f = 1 / T
Where:
c = 3.
/ m (the speed of light)
λ is the wavelengh (in meters)
T is the period (in seconds)
f is the frequency (in Hz)
We were told that:
f = 7.30 .
And we want to find out the value of λ.
c = λ / T
c = λ . 1/T
Swaping 1/T = f
c = λ . f
λ = c / f
λ = 3 .
/ 7.30 . 
λ = 4.12
m
Response: 4.12
m = 412 nm
:-)
The nervous system and the circulatory system
The advertisement is deciribing the car’s acceleration, as it gains speed when moving from 0-60.
In order for particles to perform a simple harmonic motion, we must follow the law of force of the form F = -kx, where x is the displacement of the object from the equilibrium position and k is the spring constant. The
force shown in <span>F = -kx is always the restoring force in the sense
that the particles are pulled towards the equilibrium position.
The
repulsive force felt when the charge q1 is pushed into another charge
q2 of the same polarity is given by Coulomb's law
F = </span><span>k *q1* q2 / r^2.
</span>It is clear that Coulomb's law is an inverse-square relationship. It does not have the same mathematical form as the equation <span><span>F = -kx.</span> Thus,
charged particles pushed towards another fixed charged particle of
the same fixed polarity do not show a simple harmonic motion when
released. Coulomb's law does not describe restoring force. When q1 is released, it just fly away from q2 and never returns.</span>