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goblinko [34]
3 years ago
6

a particle moves a distance of 190 ft along a straight line. As it moves, it is acted upon by a constant force of magnitude 15 l

b in a direction opposite to that of the motion. What is the work done by the force
Physics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

3868.1625 Nm

Explanation:

Given that:

Distance moved = 190 ft

Magnitude of force = 15 lb

Converting units :

1 lb = 4.45 Newton

1 ft = 0.305 meter

Hence,

Distance moved = (190 * 0.305) = 57.95 meter

Magnitude of force = (15 * 4.45) = 66.75 Newton

Workdone = Force * distance

Workdone = 66.75 N * 57.95 m

Workdone = 3868.1625 Nm

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PLEASE HELP ME!!!! I'LL MARK YOU BRAINLIEST IF YOU ANSWER THIS CORRECTLY!!!!! I NEED THESE DONE TODAY!!!!
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Answer:

<h2>1)</h2><h2>TRUE</h2><h2>2)</h2><h2>TRUE</h2><h2>3)</h2><h2>TRUE</h2><h2>4)</h2><h2>\lambda = 0.773 m</h2><h2>5)</h2><h2>v = 100 m/s</h2>

Explanation:

1)

As we know by the formula of speed of sound we have

v = 332 + 0.6 t

t = 20 deg C

v = 332 + (0.6 \times 20)

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Wave speed is given as

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f = \frac{1}{T}

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4)

Wavelength is given as

\lambda = \frac{v}{f}

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As we know that

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Explanation:

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