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Arte-miy333 [17]
2 years ago
10

What is the suns purpose

Physics
1 answer:
Bumek [7]2 years ago
7 0

Answer:

The Sun provides Life to the Earth

Explanation:

The Sun is made up of mostly Hydrogen and some Helium, and it is in delicate balance with both gravity trying to pull it in while the power of fusion pushes it outwards. The fusion creates energy, which is used to keep our delicate world in balance with the sun.

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A toy car is placed 29.0cm from a convex mirror. The image of the car is upright and one-sixth as large as the actual car. Calcu
borishaifa [10]

Answer:

The power of the mirror is -17.24 diopter.

Explanation:

Magnification of an image,m = \frac{1}{6}

Distance of the object from the mirror = u = 29.0 cm

Distance of an image from the mirror = v

Magnification = m=\frac{-v}{u}

\frac{1}{6}=\frac{-v}{u}

v=\frac{-u}{6}

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{-6}{u}

f=\frac{-u}{5}=\frac{-29.0 cm}{5}=-5.8 cm

Focal length of mirror = -5.8 cm =-0.058 m

Power of the lens = P

P =\frac{1}{f}

P=\frac{1}{-0.058 m}=-17.24 D

8 0
3 years ago
How much force is required to accelerate an 8.6kg wagon by 15 m/s ?
OverLord2011 [107]

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

<h3>What is force?</h3>

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

  • Mass of the rock m = 8.6kg
  • Acceleration a = 15m/s²
  • Force F = ?

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

Learn more about force here: brainly.com/question/27196358

#SPJ1

7 0
2 years ago
Which two types of particles are found in an atom’s nucleus?
astraxan [27]

Answer:

protrons and neutrons

Explanation:

i took a quiz with this question and got it right

7 0
3 years ago
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onsider 1000 mL of a 1.00 × 10-4 M solution of a certain acid HA that has a Ka value equal to 1.00 × 10-4. Water was added or re
solmaris [256]

Answer:

The volume of the final solution, V = 0.0305L

Explanation:

Number of moles = Concentration * volume

Concentration of HA = 1.00 * 10⁻⁴M

Volume of HA = 1000mL = 1 L

Number of moles of HA =  1.00 * 10⁻⁴ * 1

Number of moles of HA =  1.00 * 10⁻⁴ mols

Equation of reaction:

HA → H⁺  +  A⁻

If 1 mol of HA produces 1 mol of H⁺  and  A⁻, 1.00 * 10⁻⁴ mol of HA will produce 1.00 * 10⁻⁴ mol of  H⁺  and  A⁻.

Since only 16% dissociation occurs = 0.16

Number of moles of  H⁺ produced = 0.16 *  1.00 * 10⁻⁴

Number of moles of  H⁺ produced = 1.6 * 10⁻⁵mols

Number of moles of  A⁻ produced = 0.16 *  1.00 * 10⁻⁴

Number of moles of  A⁻ produced = 1.6 * 10⁻⁵mols

Since 16% of HA dissociated into  H⁺  and  A⁻, 84% of HA is left

Number of mols of HA left = 0.84 *  1.00 * 10⁻⁴

Number of mols of HA left =  8.4 * 10⁻⁵mols

Concentration = num of moles/volume

Let the volume of the final solution be V

Conc of HA = 8.4 * 10⁻⁵/V

Conc of H⁺ = 1.6 * 10⁻⁵/V

Conc of A⁻ =  1.6 * 10⁻⁵/V

To calculate the dissociation constant

k_{a} = [H^{+} ][A^{-} ]/[HA]

k_{a}= [1.6 * 10^{-5} /V][1.6 * 10^{-5} /V]/[8.4 * 10^{-5} /V]\\k_{a}= 3.05 * 10^{-6} /V\\k_{a} = 1.00 * 10^{-4}\\ 1.00 * 10^{-4} = 3.05 * 10^{-6} /V\\V= 3.05 * 10^{-6}/ 1.00 * 10^{-4}\\V=3.05 * 10^{-2}\\V=0.0305 L

3 0
3 years ago
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