For this case we first think that the skateboard and the child are one body.
We have then:
1 = jug
2 = skateboard + boy
By conservation of the linear amount of movement:
M1V1i + M2V2i = M1V1f + M2V2f
Initial rest:
v1i = v2i = 0
0 = M1V1f + M2V2f
Substituting values
0 = (7.8) (3.2) + (M2) (- 0.65)
0 = 24.96 + M2 (-0.65)
-24.96 = (-0.65) M2
M2 = (-24.96) / (- 0.65) = 38.4 kg
Then, the child's mass is:
M2 = Mskateboard + Mb
Clearing:
Mb = M2-Mskateboard
Mb = 38.4 - 1.9
Mb = 36.5 Kg
answer:
the boy's mass is 36.5 Kg
Answer:
v=77.62 m/s
Explanation:
Given that
h= - 300 m
speed of the bird ,u= 5 m/s
Lets take Speed of the berry when it hit the ground = v m/s
we know that ,if object is moving upward
v² = u² - 2 g h
u=Initial speed
v=Final speed
h=Height
Now by putting the values
v² = u² - 2 g h
v² = 5² - 2 x 10 x (-300) ( take g = 10 m/s²)
v² =25 + 20 x 300
v² ==25 + 6000
v² =6025
v=77.62 m/s
Therefore the final speed of the berry will be 77.62 m/s.
Answer:
Part A:
The proton has a smaller wavelength than the electron.
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Part B:
The proton has a smaller wavelength than the electron.
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Explanation:
The wavelength of each particle can be determined by means of the De Broglie equation.
(1)
Where h is the Planck's constant and p is the momentum.
(2)
Part A
Case for the electron:

But 


Case for the proton:


Hence, the proton has a smaller wavelength than the electron.
<em>Part B </em>
For part b, the wavelength of the electron and proton for that energy will be determined.
First, it is necessary to find the velocity associated to that kinetic energy:


(3)
Case for the electron:

but


Then, equation 2 can be used:

Case for the proton :

But 


Then, equation 2 can be used:

Hence, the proton has a smaller wavelength than the electron.
Answer: <em> a). Grip</em>
The grip is the important thing to be consider for golfer. It is the most fundamental important aspects to the game, because it provides the solid contact.
Applying the correct grip, results in better golf shots and an increased confidence to the golfer, to address the ball in the right direction.
Simply the grip is the pressure applied to the club with the hand such that the golfer feels comfortable to make a brilliant shot.
The answer, using an indicator to measure the hydrogen ion concentration of a solution, is correct