Answer:
3 * 10³J/s
Explanation:
Given :
Force applied, F = 300 N
Distance, d = 30 m
Time, t = 3 seconds
Power, P = Workdone / time
Recall :
Workdone = Force * distance
Workdone = 300 N * 30 m = 9000 Nm
Workdone = 9 * 10³ J
Power = (9 * 10³ J) / 3s
Power = 3 * 10³J/s
 
        
             
        
        
        
Answer:
The magnitude of the electric field at a point equidistant from the lines is 
Explanation:
Given that,
Positive charge = 24.00  μC/m
Distance = 4.10 m
We need to calculate the angle 
Using formula of angle



We need to calculate the magnitude of the electric field at a point equidistant from the lines
Using formula of electric field

Put the value into the formula



Hence, The magnitude of the electric field at a point equidistant from the lines is 
 
        
             
        
        
        
Answer:
acc. = 4-(-6) /5= 10/5=2 m/s^2
 
        
             
        
        
        
You said that she's losing 1.9 m/s of her speed every second.
So it'll take
             (6 m/s) / (1.9 m/s²)  =  3.158 seconds  (rounded)
to lose all of her initial speed, and stop.