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3 years ago

a solution contains 2.1 moles of HCl and has a molarity of 6.00 M what volume of the solution occupy.

1 answer:

8 0

Use the formula C = n / V

We are given the moles, n = 2.1
And the molarity, C = 6

Rearrange the formula with V as the subject:

V = n / C

Sub in your values,

V = 2.1 / 6
= 0.35 L

Hope this helped! :)

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Answer: The final temperature of both substances at thermal equilibrium is 301.0 K

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$heat_{absorbed}=heat_{released}$

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$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

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$T_{final}$ = final temperature = ?

$T_1$ = temperature of gold = $69.4^oC=342.4K$

$T_2$ = temperature of water = $27.4^oC=300.4K$

$c_1$ = specific heat of gold = $0.129J/g^0C$

$c_2$ = specific heat of water= $4.184J/g^0C$

Now put all the given values in equation (1), we get

$-31.5\times 0.129\times (T_{final}-342.4)=[63.4\times 4.184\times (T_{final}-300.4)]$

$T_{final}=301.0K$

The final temperature of both substances at thermal equilibrium is 301.0 K

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