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3 years ago

The elements selenium and oxygen are both poor electrical conductors in which section of the periodic table are they found

Chemistry

2 answers:

Nutka1998 [239]3 years ago

6 0

Answer:

This question appears incomplete

Explanation:

The periodic table is divided into 4 blocks; s-block, p-block, d-block and the f-block.

Elements found in the s-block are metals; alkali metals and alkali earth metals. Elements found in the p-block include metals and non-metals while those found in the d-block are metals (transition metals). The F-block elements are the radioactive elements.

Oxygen (O) and selenium (Se) are non-metals found in group 16 of the periodic table which is found in the p-block of the periodic table. The p-block is located on the right side of the periodic table. Generally, non-metals are poor conductors of electricity.

Strike441 [17]3 years ago

5 0

Answer:

No metals. Right side.

Explanation:

On the right. Non metallic elements

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Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO

zavuch27 [327]

Answer:

$K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}$

Explanation:

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In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

$2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons 4NOBr ( g )$

The suitable equilibrium constant turns out:

$K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}$

Or in terms of the initial equilibrium constant:

$K_2=K_1^2$

Since the second reaction is a doubled version of the first one.

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