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3 years ago

Please help me with this!!! anyone???? im in desprate need!!

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

The answer to your question is: the second option

Step-by-step explanation:

If two lines are parallel, then their slopes are the same

Slope of the lower line :

m = (-d - 0) / (0 + c)

m = -d / c

Slope of the upper line:

m = ( 0 - a) / (b - 0)

m = - a/ b

finally

-d/c = -a/b

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What is the sum of the interior angles of a regular polygon with 5 sides?

ZanzabumX [31]

Answer:

540 is the ans

Step-by-step explanation:

this is the correct answer

8 0

3 years ago

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The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago

A right rectangular prism has edges of 2 1/4 in, 1 1/2 in and 1 1/2 in. How many cubes with lengths of 1/4 in would be needed to

Zielflug [23.3K]

The volume of a rectangular prism is (length) x (width) x (height).

The volume of the big one is (2.25) x (1.5) x (1.5) = <em>5.0625 cubic inches</em>.

The volume of the little one is (0.25)x(0.25)x(0.25)= 0.015625 cubic inch

The number of little ones needed to fill the big one is

   (Volume of the big one) divided by (volume of the little one) .

   5.0625 / 0.015625 = <em>324 tiny cubies</em>

=================================================

Doing it with fractions instead of decimals:

The volume of a rectangular prism is (length) x (width) x (height).
Dimensions of the big one are:

   2-1/4 = 9/4
   1-1/2 = 3/2
   1-1/2 = 3/2

   Volume = (9/4) x (3/2) x (3/2) =

   (9 x 3 x 3) / (4 x 2 x 2) =

   81 / 16 cubic inches.

As a mixed number: 81/16 = <em>5-1/16 cubic inches</em>

Volume of the tiny cubie = (1/4) x (1/4) x (1/4) = 1/64 cubic inch.

The number of little ones needed to fill the big one is

   (Volume of the big one) divided by (volume of the little one) .

   (81/16) divided by (1/64) =

   (81/16) times (64/1) =

   5,184/16 = <em>324 tiny cubies</em>.

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3 years ago

During first semester the ratio of the number of students in art class to the number of students in gym class was 2:7. However t

elena-s [515]

5/4 = 75/g....cross multiply because this is a proportion
5g = 300
g = 300/5
g = 60
so in 2nd semester, there were 75 students in art class and 60 students in gym class....for a total of 135 students.

1st semester....ratio was 2:7...added = 9
art : 2/9(135) = 270/9 = 30 <=== art class had 30
gym: 7/9(135) = 945/9 = 105 <=== gym class had 105

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3 years ago

The area of triangle B is 25 times greater than the area of triangle A.The perimeter of triangle B is how many times greater tha

Tpy6a [65]

<span>The ratio of areas is the square of the ratio of perimeters;
The area of triangle B / The area of triangle A = 25 ;
The perimeter of triangle B / The perimeter of triangle A = </span> $\sqrt{25} = 5 ;$
The perimeter of triangle B is 5many times greater than the perimeter of<span>triangle A!</span>

7 0

3 years ago

Read 2 more answers