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alexdok [17]
3 years ago
15

What’s the answer to this ?

Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

2/5

Step-by-step explanation:

<u>The unit rate is:  change in y over change in x</u>

<em>This graph goes up 2 and moves to the right 5, that means it is 2/5</em>

<em />

Answer:  2/5

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Jason ate 1/2 of a whole pizza. The next day, he shared the remaining pizza between himself and 2 friends. What fraction of the
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Answer:

1/6

Step-by-step explanation:

jason ate 1/2, so only 1/2 of the pizza is left.

1 ÷ 2 = 1/2

he split it equally between himself and 2 friends (3 people)

1/2 ÷ 3

= 1/2 × 1/3

=1/6

8 0
3 years ago
Which is greater 3/8 or 2/3
Olenka [21]
2/3 is greater because 3/8 is less than 1/2 while 2/3 is greater than 1/2
6 0
3 years ago
Simplify the following expression. Write your answer in simplest radical form. y1/5 x y1/6
Gnoma [55]

Answer:

y1

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4 years ago
Simplify and evaluate<br><br> (6)(2^3)^2 / (2^2)^2
sveticcg [70]

Simplify and evaluate

(6)(2^3)^2 = 384

(2^2)^2 = 16

5 0
3 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
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