Answer:
(a) x = 30°
(b) mRS = 30°
mST = 120°
mTU = 120°
mUR = 90°
Step-by-step explanation:
(a) In the picture attached, the diagram is shown.
Given that m arc RS = x, from the ratios:
m arc ST = 4x
m arc TU = 4x
m arc UR = 3x
The addition of the four arcs must be equal to 360°, then:
x + 4x + 4x + 3x = 360°
12x = 360°
x = 360°/12 = 30°
(b) m arc RS = x = 30°
m arc ST = 4x = 4*30° = 120°
m arc TU = 4x = 4*30° = 120°
m arc UR = 3x = 3*30° = 90°
The diameter can be obtained by the formula A = pi*r^2
First, multiply 0.50 * 100 to obtain the area of the ball, then simplify and solve for the radius. Doubling the radius would yield the diameter. This is shown below:
Area of the ball = 0.50 * 100 = 50 in^2
<span>A = pi*r^2
</span>50 = (3.14)*r^2
r = 3.99 = approx. 4
diameter = 2r
Diameter = 8 inches.
Among the choices, the correct answer is C. 8.0 in.
The given equation of the ellipse is x^2
+ y^2 = 2 x + 2 y
At tangent line, the point is horizontal with the x-axis
therefore slope = dy / dx = 0
<span>So we have to take the 1st derivative of the equation
then equate dy / dx to zero.</span>
x^2 + y^2 = 2 x + 2 y
x^2 – 2 x = 2 y – y^2
(2x – 2) dx = (2 – 2y) dy
(2x – 2) / (2 – 2y) = 0
2x – 2 = 0
x = 1
To find for y, we go back to the original equation then substitute
the value of x.
x^2 + y^2 = 2 x + 2 y
1^2 + y^2 = 2 * 1 + 2 y
y^2 – 2y + 1 – 2 = 0
y^2 – 2y – 1 = 0
Finding the roots using the quadratic formula:
y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1
y = 1 ± 2.828
y = -1.828 , 3.828
<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828)
and (1, 3.828).</span>
Answer:
0 = (3-2x) x (x x 2 -5)
(3-2x) x ( x x 2 - 5) = 0
(3-2x) x (2x - 5) = 0
3 - 2x = 0
2x - 5 = 0
x = 3/2
x = 5/2
x1 = 3/2 or x2 = 5/2
Answer:“ C ”
“month” on the x axis and “log” on the y axis
