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Artist 52 [7]
4 years ago
8

Tim added 3/6 and 1/2 and wrote an answer of 4/12.Is Tim’s solution correct? Explain why or why not using pictures, numbers and

words
Mathematics
1 answer:
dalvyx [7]4 years ago
6 0

Answer:

Tim is wrong.

Step-by-step explanation:

3/6 can be reduced down to 1/2, and 1/2+1/2=1, not 4/12.

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Help please............
tigry1 [53]

Answer:

\tan(J) =\frac{5\sqrt{66}}{66}

Step-by-step explanation:

\tan(J) =\frac{5}{\sqrt{66}}

\tan(J) =\frac{5}{\sqrt{66}} \times \frac{\sqrt{66}}{\sqrt{66}}

\tan(J) =\frac{5\sqrt{66}}{\sqrt{66}\times\sqrt{66} }

\tan(J) =\frac{5\sqrt{66}}{66}

5 0
3 years ago
The length of a photograph of Mr. Lemley playing golf is 1475 inches. If the area
Mice21 [21]

Answer:

1.12 × 10^-3

Step-by-step explanation:

The computation of the width of the photograph is as follows:

As we know that

Area of the rectangle = length × width

33 ÷ 20 square inches = 1475 inches × width

So, the width is

= Length ÷ area

=  1475 inches ÷ (33 ÷ 20 square inches)

= 1.12 × 10^-3

8 0
3 years ago
Cindy has decided to lease a car. The lease includes a money factor of 0.0035. What
Stolb23 [73]

Answer: 1.3 is her interest rate hopefully I'm correct on this

4 0
3 years ago
Read 2 more answers
If a light ray is relflected off the shiny surface at 170 degrees, at what angle did the light ray first strike the surface?
tiny-mole [99]

Answer:

10 degrees

Step-by-step explanation:

take 180-170

and then 10 is  your answer

you only need to try to get to 180

3 0
3 years ago
Real Estate One conducted a recent survey of house prices for properties located on the shores of Tawas Bay. Data on 26 recent s
Ivanshal [37]

Answer:

Step-by-step explanation:

Hello!

Given the data for the variables:

Y: Selling price of a house on the shore of Tawas Bay

X₁: Number of bathrooms of a house on the shore of Tawas Bay.

X₂: Square feet of a house on the shore of Tawas Bay.

X₃: Number of bedrooms of a house on the shore of Tawas Bay.

The multiple regression model is Y= α + β₁X₁ + β₂X₂ + β₃X₃ + εi

a. Using software I've entered the raw data and estimated the regression coefficients:

^α= a= -5531.01

Represents the mean selling price of the houses when 0 bathrooms, 0 square feet and 0 bedrooms.

^β₁= b₁= -1386.21

Represents the modification of the mean selling price of the houses when the number of bathrooms increases in one unit and the square feet and number of bedrooms remain unchanged.

^β₂= b₂= 60.28

Represents the modification of the mean selling price of the houses when the square feet increase in one unit and the number of bathrooms and bedrooms remain unchanged.

^ β₃= b₃= 54797.08

Represents the modification of the mean selling price of the houses when the number of bedrooms increase in one unit and the number of bathrooms and square feet of the houses remain unchanged.

^Y= -5531.01 -1386.21X₁ + 60.28X₂ + 54797.08X₃

b)

R²= 0.55

R²Aj= 0.49

The coefficient of determination gives you an idea of how much of the variability of the dependent variable (Y) is due to the explanatory variables. Each time you add another explanatory variable to the regression the coefficient increases regarding of real contribution of the new variable. This could lead to thinking (wrongly) that the new variables are good to explain the dependent variable.  

The adjusted coefficient of determination is a correction made to the raw coefficient of determination to have a more unbiased estimation of the effect the independent variables have over the dependent variable.

⇒ As you can see both coefficient are around 50%, which means that these explanatory variables

c)

The standard error estimate, this is the estimate of the population variance of the errors. In the ANOVA is represented by the Mean Square of the errors (MME)

Se²= MME= 3837640577.01

Se= 61948.6931

d) and f)

For the hypotheses tests for each slope the t- and p-values are:

α: 0.05

β₁: t_{H_0}= \frac{b_1-\beta_1 }{Sb_1} t= -0.06; p-value: 0.9528 ⇒ Do not reject H₀, the test is not significant.

β₂: t_{H_0}= \frac{b_2-\beta_2 }{Sb_2} t= 2.56; p-value: 0.0180 ⇒ Reject H₀, the test is significant.

β₃: t_{H_0}= \frac{b_3-\beta_3 }{Sb_3} t= 2.28; p-value: 0.0326 ⇒ Reject H₀, the test is significant.

e)

H₀: β₁= β₂= β₃

H₁: At least one βi is different from the others ∀ i=1, 2, 3

α: 0.05

F= 9.03

p-value: 0.0004

⇒ Reject H₀, the test is significant.

I hope it helps!

5 0
3 years ago
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