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3 years ago

Help please............

Mathematics

1 answer:

tigry1 [53]3 years ago

5 0

Answer:

$\tan(J) =\frac{5\sqrt{66}}{66}$

Step-by-step explanation:

$\tan(J) =\frac{5}{\sqrt{66}}$

$\tan(J) =\frac{5}{\sqrt{66}} \times \frac{\sqrt{66}}{\sqrt{66}}$

$\tan(J) =\frac{5\sqrt{66}}{\sqrt{66}\times\sqrt{66} }$

$\tan(J) =\frac{5\sqrt{66}}{66}$

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Plz help I will do anything

Basile [38]

There's no need to get into an ethical morass over math homework.

111.

M is 20% less than N means

M is 100-20=80% of N

M=0.80 N

M/N = 0.8 = 4/5

Ratio: 4/5

112.

When we know a, the average, and n, how many numbers there are, we know the sum s, because a=s/n so s=na.

So the sum of our six numbers is 6(3.5)=21 so the sum of the seven numbers is 21+4.2=25.2 so the average is 25.2/7 = 3.6

Answer: 3.6

113.

|2p + 4 | < 3

At p=-2 the absolute value is zero. As p gets more negative the absolute value argument (inside part) gets negative and the absolute value gets bigger, more positive. Eventually the inside will be exactly -3, when

2p +4 = -3

2p = -7

p = -7/2 = -3 1/2

So p=-4 will make the inequality false, and p=-3 is the smallest integer that makes the inequality true.

Answer: -3

114.

The distance from the origin is given by the Pythagorean Theorem and this one is a 3/4/5 right triangle:

$d = \sqrt{(-.3)^2 + (-.4)^2}=.5$

Answer: .5 or 1/2

4 0

3 years ago

Gretchen has a set of blocks of heights 1, 2, and 4-centimeters. Imagine stacking the blocks one on top of the other to make a t

notsponge [240]

Answer:

$t_{n}$ = $t_{n-1}$ + $t_{n-2}$ + $t_{n-4}$

Step-by-step explanation:

$t_{n}$ =multiple ways to climb a tower

When n = 1,

tower= 1 cm

$t_{1}$ = 1

When n = 2,

tower =2 cm

$t_{2}$ = 2

When n = 3,

tower = 3 cm

it can be build if we use three 1 cm blocks

$t_{3}$ = 3

When n = 4,

tower= 4 cm

it can be build if we use four 1 cm blocks

$t_{4}$ = 6

When n > 5

tower height > 4 cm

so we can use 1 cm, 2 cm and 4 cm blocks

so in that case if our last move is 1 cm block then $t_{n-1}$ will be

n —1 cm

if our last move is 2 cm block then $t_{n-2}$ will be

n —2 cm

if our last move is 4 cm block then $t_{n-4}$ will be

n —4 cm

$t_{n}$ = $t_{n-1}$ + $t_{n-2}$ + $t_{n-4}$

4 0

4 years ago

Read 2 more answers

Please help me someone

FinnZ [79.3K]

Step-by-step explanation:

Your answers are given in the attachment

please check it once if it is helpful to you or not

7 0

3 years ago

Math question help me

Rufina [12.5K]

Answer:

the 4th one

Step-by-step explanation:

i'm pretty sure that's right

5 0

3 years ago

he lifespan of the Ebola virus on flat dry surfaces has a normal distribution with μ = 643.6 minutes and σ = 77.7 minutes. You m

Vedmedyk [2.9K]

Answer:

By the Central Limit theorem, the mean of the distribution of sample means is 643.6 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem

The mean of the population is 643.6 minutes.

By the Central Limit theorem, the mean of the distribution of sample means is 643.6 minutes.

5 0

4 years ago