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pantera1 [17]
3 years ago
12

Help please............

Mathematics
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

\tan(J) =\frac{5\sqrt{66}}{66}

Step-by-step explanation:

\tan(J) =\frac{5}{\sqrt{66}}

\tan(J) =\frac{5}{\sqrt{66}} \times \frac{\sqrt{66}}{\sqrt{66}}

\tan(J) =\frac{5\sqrt{66}}{\sqrt{66}\times\sqrt{66} }

\tan(J) =\frac{5\sqrt{66}}{66}

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Solve the following simultaneous equations.<br> 5x – 3y = 6<br> 3x + 4y= 21
ehidna [41]

Answer:

y  = 3, x = 3

Step-by-step explanation:

5x – 3y = 6

5x = 6 + 3y

x = (6 + 3y)/5

3x + 4y= 21

3x = 21 - 4y

x = (21-4y)/3

Using simultaneous equations:

(21-4y)/3 = (6 + 3y)/5

--> 105-20y = 18 + 9y

29y = 87

  • y = 3

  • x = (6 + 3(3))/5 = 3
3 0
2 years ago
Pls help need it quickly
spayn [35]
Hey boo! The answer is 0.000001. Have a lovely day!
3 0
3 years ago
Read 2 more answers
What is the slope of the line? y + 5=2(x+1)
mel-nik [20]

Answer:

2

Step-by-step explanation:

So we have the equation:

y+5=2(x+1)

This is in the format point-slope form, where:

y-y_1=m(x-x_1)

Here, m is the slope.

In our original equation, 2 replaces m.

Therefore, our slope is 2.

5 0
3 years ago
Read 2 more answers
Please help!!!!! it's a word problem and I don't understand how to do it at all
andre [41]
7We can see that line NM = JK so NM also equals 10.
We know NL = 23 and NM = 10 therefore, ML = NL -NM  ML = 23 -13
ML = 10
The last thing to solve is the length of KL
KL = ML / sine 34
KL = 10 / 0.55919
KL = 17.9

Total fence length required = JK + KL + NL =
13 + 17.9 + 23
= 53.9 yards
Cost of Fencing = $3.50 * 53.9 =
<span> <span> <span> $188.65 </span> </span> </span>



8 0
3 years ago
In six grade class, 3/7 of the students are boys, and 5/8 of these boys are in Ms. Jones’ class. What fraction of the entire six
Damm [24]

Think of the entire population of 6th graders here. 3/7 are boys and 4/7 are girls. 5/8 of these boys are in Ms. Jones' class; that fraction would be (5/8)(3/7), or 15/56. This 15/56 represents the fraction of the entire sixth grade class who are in Ms. Jones' class.


8 0
3 years ago
Read 2 more answers
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