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anastassius [24]
3 years ago
11

A hiker leaves camp and walks 6 miles east. Then he walks 18 miles south. How far from camp is the hiker? Distance in miles: Usi

ng quadratic applications

Mathematics
1 answer:
Mrac [35]3 years ago
5 0

Answer: 19 miles

Step-by-step explanation:

Hi, since the situation forms a right triangle (see attachment) we have to apply the Pythagorean Theorem:  

c^2 = a^2 + b^2  

Where c is the hypotenuse of the triangle (in this case the distance between the hiker and the camp) and a and b are the other sides.  

Replacing with the values given:  

x^2 = 6^2 + 18^2  

x^2 = 36+324

x^2 = 360

x = √360

x = 18.97miles = 19 miles

Feel free to ask for more if needed or if you did not understand something.  

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According to the statement

we have to find that the standard deviation, mean and the intervals from the given data.

So, According to the given data from the method of tree ring dating

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∑(xi - x-bar)^2 = (-2)2 + (-65)2 + (-44)2 + ... + (2)2

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So, standard deviation is 37 years.

We need the t-distribution table since the standard deviation is unknown.  Therefore, our degrees of freedom is 9 - 1 = 8 and the critical value is 1.860.  Set up the confidence interval for the mean:

[x-bar ± t*(s/√n)] = [1273 ± 1.860*(37/√9)]

[x-bar ± t*(s/√n)] = [1250,1296]

So, The value of mean, standard deviation and interval from the method of tree ring dating is 1273 AD, 37 years, [1250,1296].

Learn more about method of tree ring dating here

brainly.com/question/15107034

Disclaimer: This question was incomplete. Please find the full content below.

Question:

The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.

For more data please see the image below.

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