Answer:
a. There is little or no change in the entropy.
b. ΔS is greater than zero.
c. There is little or no change in the entropy.
d. ΔS is less than zero.
e. ΔS is greater than zero.
Explanation:
The change in the entropy (ΔS) depends on the change in the amount of gaseous moles, Δn(g) = ngas, products - ngas,reactants.
- If Δn(g) > 0, the entropy increases (ΔS > 0)
- If Δn(g) < 0, the entropy decreases (ΔS < 0)
- If Δn(g) = 0, there is little or no change in the entropy.
<em>a. I₂(g) + Cl₂(g) → 2 ICl(g)</em>
Δn(g) = 2 - 2 = 0. There is little or no change in the entropy.
<em>b. PCl₅(g) → PCl₃(g) + Cl₂(g)</em>
Δn(g) = 2 - 1 = 1. ΔS is greater than zero.
<em>c. CO₂(g) + H₂(g) → H₂O(g) + CO(g)</em>
Δn(g) = 2 - 2 = 0. There is little or no change in the entropy.
<em>d. 2 CO(g) + 2 NO(g) → 2 CO₂(g) + N₂(g)</em>
Δn(g) = 3 - 4 = -1. ΔS is less than zero.
<em>e. 2 H₂O₂(l) → 2 H₂O(l) + O₂(g)</em>
Δn(g) = 1 - 0 = 1. ΔS is greater than zero.
