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Anuta_ua [19.1K]
3 years ago
15

How can the hemlock woolly upset natural ecosystem?

Chemistry
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

The HWA attacks eastern hemlock trees in forests and ornamental hemlock trees found in our residential landscaping. It feeds on the hemlock trees' young twigs by sucking the sap, causing their buds to die and needles to dry out and drop from the plant prematurely i think

hope i helped!!

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Sulfuric acid is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that sulfuric acid can under
Dmitriy789 [7]

Answer:

H₂SO₄ (aq) + H₂O (l)  → HSO₄⁻ (aq) + H₃O⁺ (aq)

HSO₄⁻ (aq) + H₂O (l) ⇄  SO₄⁻²(aq) + H₃O⁺ (aq)           Ka

Explanation:

The sulfuric acid is a dyprotic acid.

It is a considered a strong acid but only the first deprotonation is strong.

Second deprotonation is totally weak

That's why we have equilibrium when it release the second proton.

Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium

4 0
3 years ago
The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r
rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

    = 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the  rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

K=Ae^{\frac{-E}{RT}}

If K_1=Ae^{\frac{-E_1}{RT}} -------equation 1     &

K_2=Ae^{\frac{-E_2}{RT}} -------equation 2

\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}

E_1= E_2-RT*In(\frac{K_1}{K_2})

E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})

E_1 = 28957.39292  J/mol

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0
3 years ago
Metal atoms tend to give away valence electrons when they bond with nonmetal atoms. What type of bond will form between the meta
jek_recluse [69]
An ionc bond because electrons are transferred, creating a positive metal cation and negative nonmetal anion which attracts one another electrostatically.
6 0
3 years ago
Read 2 more answers
the countercurrent arrangement of the two limbs of the loop of henle becomes a multiplier of electrolyte concentration due to wh
enot [183]

The counter-current is the process that occurs in the excretory system. The limbs become the multiplier because of the active transport of the electrolytes that move out.

<h3>What is the loop of Henle?</h3>

The loop of Henle is the part of the excretory system and part of the nephron. It functions in minimizing the water loss in the excretion of urine. There are descending and ascending loops present.

The ascending loop is impermeable to water but permeable to the electrolytes, and hence the concentration of the sodium, potassium, and chloride ions are actively pumped. This makes the solution more concentrated in the ascending loop.

Therefore, the electrolyte concentration results in active transport.

Learn more about the loop of Henle here:

brainly.com/question/13191804

#SPJ4

5 0
2 years ago
6)
scZoUnD [109]

Answer:

A.) Linear

Explanation:

4 0
3 years ago
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