Answer:
47.9L of oxygen would be required
Explanation:
<em>Assuming oxygen gas is at STP</em>
Based on the reaction:
S₈ + 12 O₂ → 8SO₃
1 mole of S₈ (Molar mass: 256.52g/mol) reacts with 12 moles of oxygen.
To solve this question we must find the moles of S₈ added. With the reaction we can find the moles of O₂ and using PV = nRT we can find the volume of oxygen required:
<em>Moles S₈:</em>
45.7g * (1mol / 256.52g) = 0.178 moles S₈
<em>Moles O₂:</em>
0.178 moles S₈ * (12 moles O₂ / 1mol S₈) = 2.138 moles O₂
<em>Volume O₂:</em>
PV = nRT
V = nRT / P
<em>Where V is volume</em>
<em>n are moles = 2.138 moles</em>
<em>R is gas constant 0.082atmL/molK</em>
<em>T is absolute temperature = 273.15K at sTP</em>
<em>P is pressure = 1 atm at STP</em>
<em />
V = 2.138mol*0.082atmL/molK*273.15K / 1atm
V = 47.9L of oxygen would be required
Answer:
3.011 × 10²³ atoms of Al
Explanation:
Given data:
Number of moles of Al₂(SO₄)₃ = 0.25 mol
Number of atoms of Al = ?
Solution:
In one mole of Al₂(SO₄)₃ there are 2 moles of Al.
In 0.25 mol × 2 = 0.5 mol
1 mole of any substance contain 6.022 × 10²³ atoms.
In 0.5 moles of Al:
1 mole contain 6.022 × 10²³ atoms.
0.5 mol × 6.022 × 10²³ atoms/ 1 mol
3.011 × 10²³ atoms
Answer:
I think carbon and hydrogen
Answer:
Double=4 and triple=6
Explanation:
This is because double bonds are two pairs of electrons are shared between atoms and triple bonds are three pairs, and one pair of electrons is 2, so 2 x 2=4 and 2 x 3=6.
D NACL because it is ionic bond and all the others are covalent
