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musickatia [10]
2 years ago
15

What is the distance and midpoint of (-2,-2) and (3,5)​

Mathematics
1 answer:
yuradex [85]2 years ago
4 0

Answer:

2-5

Step-by-step explanation:

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Step-by-step explanation:

(x−1)²−9=0

(x-1)²= 9

x-1 = ±√9

x-1 = ±3

x = 1-3=-2 or x=1+3=4

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2 years ago
Answer the questions by drawing on the coordinate plane below.
solniwko [45]

Coordinates of the given triangle ΔPQR P(1,-1), Q(3,-2), R(3,-4).

a) Let us discuss the rule for rotation of 90° clockwise about the origin.

If given coordinate is (h,k) is rotated 90° clockwise about the origin the position of rotated coordinate will be (k, -h).

x and y coordinates would switch their values and after switching x any values, the y value of the coordinates would reverse in sign.

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P'(-1,-1)

Q(3,-2) --> Q'( -2,-3)

R(3,-4) --> R'(-4,-3)

b) If given coordinate is (h,k), the coordinates after reflection across the x-axis would besome (h,-k). (Just change in the sign of y-coordinate).

So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become

P(1,-1) --> P"(1,1)

Q(3,-2) --> Q"( 3,2)

R(3,-4) --> R"(3,4)



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Solve the inequality -4y+6<-4
svet-max [94.6K]

Answer:

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Step-by-step explanation:

-4y+6<-4 subtract 6 from both sides

-4y + 6 - 6 < -4 - 6 = -4y < -10 since both sides are negative we multiply it by -1 and get ➡ 4y < 10

Now divide both sides by 4

4y ÷ 4 < 10 ÷ 4 ➡ y < 5/2

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