Answer:Sources of lead emissions vary from one area to another. At the national level, major sources of lead in the air are ore and metals processing and piston-engine aircraft operating on leaded aviation fuel. Other sources are waste incinerators, utilities, and lead-acid battery manufacturers. The highest air concentrations of lead are usually found near lead smelters.
Explanation:
Answer:
13.5g of AgNO3 will be needed
Explanation:
Silver nitrate, AgNO3 contains 1 mole of silver, Ag, per mole of nitrate. To solve this problem we need to convert the mass of Ag to moles. Thee moles = Moles of AgNO3 we need. With the molar mass of AgNO3 we can find the needed mass:
<em>Moles Ag-Molar mass: 107.8682g/mol-</em>
8.6g * (1mol / 107.8682g) = 0.0797 moles Ag = Moles AgNO3
<em>Mass AgNO3 -Molar mass: 169.87g/mol-</em>
0.0797 moles Ag * (169.87g/mol) =
<h3>13.5g of AgNO3 will be needed</h3>
Answer:
The answer to your question is Dermis
Explanation:
Below the epidermis is the dermis. This is where our blood vessels, nerve endings, sweat glands, and hair follicles are.
The total number of electron pairs that are shared between the two carbon atoms in a molecule of ethyne is 3.
Answer:
1.33 x 10⁻³ mol/L
Explanation:
The solubility of a gas in a liquid is directly proportional to its partial pressure .This is know as Henry´s law and is given by the formula:
S(g) = Kh x P
where S = solubility of the gas
Kh = henry´s constant for the gas
P = partial pressure of the gas above solution
we are told to assume that the composition of the air in the tank is the same as on land, hence its partial pressure and we know nitrogen composition in air is 78 %, so the partial pressure of N₂ is:
P N₂ = 0.78 x 2.73 atm = 2.13 atm
Now we can calcualte the solubility as follows:
S N₂ = 6.26 x 10⁻⁴ mol / L·atm x 2.13 atm = 1.33 x 10⁻³ mol/ L
