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2 years ago

How many grams of silver nitrate will be needed to produce 8.6 g of silver?

Chemistry

1 answer:

konstantin123 [22]2 years ago

3 0

Answer:

13.5g of AgNO3 will be needed

Explanation:

Silver nitrate, AgNO3 contains 1 mole of silver, Ag, per mole of nitrate. To solve this problem we need to convert the mass of Ag to moles. Thee moles = Moles of AgNO3 we need. With the molar mass of AgNO3 we can find the needed mass:

<em>Moles Ag-Molar mass: 107.8682g/mol-</em>

8.6g * (1mol / 107.8682g) = 0.0797 moles Ag = Moles AgNO3

<em>Mass AgNO3 -Molar mass: 169.87g/mol-</em>

0.0797 moles Ag * (169.87g/mol) =

<h3>13.5g of AgNO3 will be needed</h3>

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Answer:

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3 years ago

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Answer:

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2 years ago

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Rudiy27

Answer:

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3 years ago

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3 years ago

Read 2 more answers