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Lerok [7]
3 years ago
6

How many grams of silver nitrate will be needed to produce 8.6 g of silver?

Chemistry
1 answer:
konstantin123 [22]3 years ago
3 0

Answer:

13.5g of AgNO3 will be needed

Explanation:

Silver nitrate, AgNO3 contains 1 mole of silver, Ag, per mole of nitrate. To solve this problem we need to convert the mass of Ag to moles. Thee moles = Moles of AgNO3 we need. With the molar mass of AgNO3 we can find the needed mass:

<em>Moles Ag-Molar mass: 107.8682g/mol-</em>

8.6g * (1mol / 107.8682g) = 0.0797 moles Ag = Moles AgNO3

<em>Mass AgNO3 -Molar mass: 169.87g/mol-</em>

0.0797 moles Ag * (169.87g/mol) =

<h3>13.5g of AgNO3 will be needed</h3>

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Part A:
uranmaximum [27]

Answer:

Part A = The mass of sulfur is 6.228 grams

Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams

Explanation:

Part A

Step 1: Data given

A mixture of carbon and sulfur has a mass of 9.0 g

Mass of the product = 27.1 grams

X = mass carbon

Y = mass sulfur

x + y = 9.0  grams

x = 9.0 - y

x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6

(9 - y)*(44.01/12.01) + y(64.07/32.07)

(9-y)(3.664) + y(1.998)

32.976 - 3.664y + 1.998y = 22.6

-1.666y = -10.376

y = 6.228 = mass sulfur

x = 9.0 - 6.228 = 2.772 grams = mass C

The mass of sulfur is 6.228 grams

Part B

Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).

Calculate moles of 1 silver atom

Moles = 1/ 6.022*10^23

Moles = 1.66*10^-24 moles

Mass = moles * molar mass

Mass = 1.66*10 ^-24 moles *107.87

Mass = 1.79 * 10^-22 grams

The mass of 1 silver atom is 1.79 * 10^-22 grams

5 0
3 years ago
Read 2 more answers
What model is the basis for chemistry?<br> Group of answer choices
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Answer:

bohrs atomic model

Explanation:

6 0
3 years ago
Bugaboo can be oxidised to a carboxylic acid by heating with acidified potassium manganate (VII). Give the name and structural f
Novosadov [1.4K]

Answer:

See below.

Explanation:

CH3CH2CH2CH2OH is butanol.

The carboxylic acid formed , butyric acid has the formula:

CH3CH2CH2COOH.

Structural formula:

       H     H    H       O                  

        |       |      |        ||                      

H  -  C  -  C  -  C   -  C  -  OH

       |       |       |    

      H     H     H

8 0
3 years ago
If 8.700 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final tem
leonid [27]
C₆H₆ is benzene which has a molar mass of 78 g/mol. When benzene is burned, the reaction is called combustion. The heat produced in this reaction is called the heat of combustion. For benzene, the heat of combustion is -3271 kJ/mol.

Heat of benzene = (8.7 g)(1 mol/78 g)(-3271 kJ/mol) = -364.84 kJ

By conservation of energy,
Heat of benzene = - Heat of water
where
Heat of Water = mCp(Tf - T₀)
where Cp for water is 4.187 kJ/kg·°C

Thus,

-364.84 kJ = -(5691 g)(1 kg/1000 g)(4.187 kJ/kg·°C)(Tf - 21)
<em>Tf = 36.31°C</em>
8 0
3 years ago
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